谁来帮忙看一下这个题错在哪里？

Winter_moon

Cryptoquote

7 B! {' B( J* q2 w; c
; L0 l- D' K& Q$ C* Y5 tTime Limit: 1000 ms Memory Limit: 65536 kB
Solved: 79 Tried: 281
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1 M) S3 D3 ]5 X! z1 d* ]Description
6 }3 X/ k! t$ e/ ]  L) ?A cryptoquote is a ** encoded message where one letter is simply replaced by another throughout the message. For example:

Encoded: HPC PJVYMIY
Decoded: ACM CONTEST

In the example above, H=A, P=C, C=M, J=O, V=N, Y=T, M=E and I=S. For this problem, you will decode messages.


# ]* W' A- Y9 b8 S1 V7 ~Input
The first line of input contains a single integer N,(1<=N<=1000) which is the number of data sets that follow. Each data set consists of two lines of input. The first line is the encoded message. The second line is a 26 character string of upper case letters giving the character mapping for each letter of the alphabet: the first character gives the mapping for A, the second for B and so on. Only upper case letters will be used. Spaces may appear in the encoded message, and should be preserved in the output string.
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Output
. B  L, |4 Z- u' `  U/ eFor each data set, you should generate one line of output with the following values: The data set number as a decimal integer (start counting at one), a space and the decoded message.
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( E# ?& M- H7 l6 XSample Input
2
# o& p$ O* q  K$ z# ]% e1 OHPC PJVYMIY
BLMRGJIASOPZEFDCKWYHUNXQTV
FDY GAI BG UKMY
+ Z' m/ M" n  M; pKIMHOTSQYRLCUZPAGWJNBVDXEF



( c7 a, j% |) |$ ~Sample Output
1 ACM CONTEST
2 THE SKY IS BLUE
( C) o8 d& N$ T
3 @$ j9 Z: P3 J
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# `' F% Y) }+ ^我的代码是：
8 s2 b, @# k, _5 B- Z#include<stdio.h>
5 A! c5 z" s0 a( O2 }8 a#include<string.h>
int main()
{
8 N3 i3 @1 ]  `; H" O" O     int N,i,j,k;
% y7 v  e0 m& m4 e+ D1 [2 @1 t     char c;
2 k) i" [4 @: O5 r     char code[1000];
     char map[27];
$ F4 O$ R* w$ w# J/ C' _/ G     char trans[1000];
     char wrong[3];
     scanf("%d",&N);
" R4 a1 F0 r2 K% S( y7 h3 E8 t     gets(wrong);
& }* |- j5 b0 |7 ^2 t) U     int h=1;
     while(N--)
9 }) d. p! t) S0 }. h  v! ?6 i     {
         gets(code);
         gets(map);
* c# a- @# b. ]- a7 d         for(i=0;((c=code[i])!='\0');i++)
         {
  t) H. e' X4 N             if(c==' ')trans[i]=' ';
, o- K0 R$ S1 K: y$ ^             else {j=code[i]-'A';
! K. X! v/ ^" [. g2 k, s             trans[i]=map[j];}       }
6 A1 C& Z8 k4 J2 Y         printf("%d ",h);
         for(i=0;((k=trans[i]<=90)&&(k=trans[i]>=65)||(k=trans[i]==' '));i++)
         printf("%c",trans[i]);
         h++;
         printf("\n");
: e: L$ h  d# Q8 t8 a     }
     return 0;
}


0 P+ y0 j- `2 ?) J2 }4 _4 u样例过了，但是提交答案的时候还是wrong answer。是哪里有陷阱？
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zjqylcy

把答案也附上来吗。。。
是不是k是int型？

葉_浅浅

.....................

linmatsas

C………………………………

_我还活着

没有看懂.....

huangliao6252

int h=1;这个定义应该在 scanf("%d",&N);前面。