谁来帮忙看一下这个题错在哪里？

Winter_moon

Cryptoquote


Time Limit: 1000 ms Memory Limit: 65536 kB
Solved: 79 Tried: 281

. X- M1 |' N/ ^! cDescription
A cryptoquote is a ** encoded message where one letter is simply replaced by another throughout the message. For example:
0 o& q/ P0 V6 Z' f; W4 ^* `, F+ g
Encoded: HPC PJVYMIY
2 e4 f- R+ K, Z0 p- p9 d' ?; H( E( @Decoded: ACM CONTEST
$ _3 [8 Q6 v+ ]" ]  D
In the example above, H=A, P=C, C=M, J=O, V=N, Y=T, M=E and I=S. For this problem, you will decode messages.

+ G% E( K! w: }& C2 m- x  k& `' l  s
  F6 L, I  ]' {3 \Input
/ W+ p6 g' [& U. HThe first line of input contains a single integer N,(1<=N<=1000) which is the number of data sets that follow. Each data set consists of two lines of input. The first line is the encoded message. The second line is a 26 character string of upper case letters giving the character mapping for each letter of the alphabet: the first character gives the mapping for A, the second for B and so on. Only upper case letters will be used. Spaces may appear in the encoded message, and should be preserved in the output string.
! Z9 Z2 P- f% j


/ y" L( R/ @- X+ G& sOutput
, g, f7 s8 W; y; z6 J+ _. gFor each data set, you should generate one line of output with the following values: The data set number as a decimal integer (start counting at one), a space and the decoded message.

+ g3 X+ L' q; n, U
Sample Input
' i0 j! W7 h' Z# R2 s* }6 B/ a2
0 `7 o  [/ n: d1 q. {HPC PJVYMIY
8 z1 ]2 s; ?2 cBLMRGJIASOPZEFDCKWYHUNXQTV
FDY GAI BG UKMY
KIMHOTSQYRLCUZPAGWJNBVDXEF
# F3 K# }8 ]9 A8 |/ Q9 G


- f' F4 r6 G9 o( }. @# nSample Output
1 ACM CONTEST
2 THE SKY IS BLUE
; K( s% O: q7 c- G9 l& w


我的代码是：
#include<stdio.h>
#include<string.h>
) D& |5 ?1 ]: ~int main()
{
     int N,i,j,k;
     char c;
     char code[1000];
/ Q: F* I. f/ g     char map[27];
, x  V/ h$ s) B4 ~, L% a     char trans[1000];
     char wrong[3];
     scanf("%d",&N);
     gets(wrong);
     int h=1;
     while(N--)
     {
  {' O+ d. {! @. \! {7 l         gets(code);
3 k, p& `- C4 G  I) L! ~) l5 \3 k         gets(map);
         for(i=0;((c=code[i])!='\0');i++)
         {
             if(c==' ')trans[i]=' ';
2 s6 y2 D9 s7 W" a4 [  k; d             else {j=code[i]-'A';
             trans[i]=map[j];}       }
         printf("%d ",h);
         for(i=0;((k=trans[i]<=90)&&(k=trans[i]>=65)||(k=trans[i]==' '));i++)
         printf("%c",trans[i]);
0 N8 G/ H& o9 f9 |- a( H- [         h++;
7 S& r: z# f6 ^1 T! M. p" d% M$ H6 y         printf("\n");
     }
0 U# O. l; ]# G8 n9 H6 w+ {     return 0;
}
7 y  w: U7 ~7 D- B3 {

样例过了，但是提交答案的时候还是wrong answer。是哪里有陷阱？
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zjqylcy

把答案也附上来吗。。。
5 c6 |- V+ m; V6 |0 e- C是不是k是int型？

葉_浅浅

.....................

linmatsas

C………………………………

_我还活着

没有看懂.....

huangliao6252

int h=1;这个定义应该在 scanf("%d",&N);前面。