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没有找到最优解,不知道哪里错了,求助各位大神,

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  • TA的每日心情
    郁闷
    2014-12-20 22:54
  • 签到天数: 1 天

    [LV.1]初来乍到

    自我介绍
    数模爱好者
    跳转到指定楼层
    1#
    发表于 2014-4-4 11:22 |只看该作者 |倒序浏览
    |招呼Ta 关注Ta
    原来的模型:



    Model:
    SETS:
    Stream/1..8/:F; !the number of streams;
    Com/1..3/:r;!the number of components,1,2,3=B,E,W;
    Dis/1..2/:N,Nmin,RR,Rmin,QC,QR,O;!number of units operation or the sets of parameters;
    Con(Stream,Com):x;!the component concentration of each stream;
    Vol(Dis,Com):a;! relative volatility;
    ENDSETS
    DATA:
    a=2 2.5 1
      2.1 1 0.4;
    r=30.783 41.5 43.94;!latent heat of three components;
    ENDDATA
    min=N(1)+N(2)+QC(1)+QC(2)+QR(1)+QR(2);
    F(1)=100000;
    F(7)=20000;
    F(8)=80000;
    x(1,1)=0;x(1,2)=0.8;x(1,3)=0.2;x(2,1)=1;x(2,2)=0;x(2,3)=0;
    x(8,2)=0.98;
    x(7,3)=0.90;
    @FOR(Com(I):F(1)*x(1,I)+F(3)*x(3,I)=F(4)*x(4,I));
    @FOR(Com(I):F(5)*x(5,I)+F(2)*x(2,I)=F(6)*x(6,I));
    @FOR(Com(I):F(4)*x(4,I)=F(5)*x(5,I)+F(7)*x(7,I));
    @FOR(Com(I):F(6)*x(6,I)=F(3)*x(3,I)+F(8)*x(8,I));
    F(1)+F(3)=F(4);
    F(4)=F(5)+F(7);
    F(5)+F(2)=F(6);
    F(6)=F(3)+F(8);
    @FOR(Stream(I)SUM(Com(J):x(I,J))=1);
    Nmin(1)=@log(x(5,1)*x(7,3)/(x(5,3)*x(7,1)))/@log(a(1,1));
    Nmin(2)=@log(x(3,1)*x(8,2)/(x(3,2)*x(8,1)))/@log(a(2,1));
    @SUM(Com(I):a(1,I)*x(4,I)/(a(1,I)-O(1)))=0;
    @SUM(Com(I):a(2,I)*x(6,I)/(a(2,I)-O(2)))=0;
    Rmin(1)=@SUM(Com(I):a(1,I)*x(5,I)/(a(1,I)-O(1)))-1;
    Rmin(2)=@SUM(Com(I):a(2,I)*x(3,I)/(a(2,I)-O(2)))-1;
    RR(1)=1.3*Rmin(1);
    RR(2)=1.3*Rmin(2);
    @FOR(Dis(K)N(K)-Nmin(K))/(N(K)+1)=0.75*(1-@POW(((R(K)-Rmin(K))/(R(K)+1)),0.566)));
    QC(1)=@SUM(Com(I):x(5,I)*r(I))*F(5)*(RR(1)+1);
    QR(1)=@SUM(Com(I):x(7,I)*r(I))*F(5)*(RR(1)+1);
    QC(2)=@SUM(Com(I):x(3,I)*r(I))*F(3)*(RR(2)+1);
    QR(2)=@SUM(Com(I):x(8,I)*r(I))*F(3)*(RR(2)+1);
    x(3,2)=0.8933-1.0724*x(3,1);
    x(5,2)=0.8933-1.0724*x(5,1);
    x(4,2)-0.8933+1.0724*x(4,1)<0;
    x(4,2)-(17/12)*x(4,1)>0;
    x(6,2)-0.8933+1.0724*x(6,1)>0;
    x(6,2)-1+(30*x(6,1))/23<0;
    x(3,1)>=0.36;
    x(3,1)<=0.46;
    x(5,1)<0.36;
    x(5,1)>0;
    END


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