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升级   79.5% TA的每日心情 | 奋斗 2016-1-29 12:24 |
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签到天数: 81 天 [LV.6]常住居民II
- 自我介绍
- 数学建模准备中...
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gancm 发表于 2014-7-19 12:30 ![]()
& _' h' F, x! c6 q/ o! W) Z看了图我感觉是网络输出后面那几个值太大了,前面基本都是一条水平线了,具体哪里还看不出问题。你把修改的 ...
/ m2 T* L# S' t因为版本更新,Matlab中的Newff命令用法有所改变,原命令为:
1 H. r5 s" q8 y9 p+ Anet=newff(dx,[3,7,2]{'tansig','tansig','purelin'},'traingdx');; c2 j) J$ G6 H+ U3 S7 d3 Q0 ~
我修改为:
9 N8 \: R4 t- Snet=newff(p,t,[3,7,2],{'tansig','tansig','purelin'},'traingdx');
a* m. j9 k9 h2 ?9 l& o& k然后有些命令被其他命令替代了,其中有premnmx,postmnmx,tramnmx命令好像被替换了,使用了一个强大的命令mapminmax。原命令为:
% e( ]' Y& f6 A# T[pn,minp,maxp,tn,mint,maxt]=premnmx(p,t);
/ k# J5 k6 Z+ f! H4 Fa=postmnmx(an,mint,maxt); L% t, j4 o+ Y& f! f
pnewn=tramnmx(pnew,minp,maxp);
* ~. B0 ]. {/ \anew=postmnmx(anewn,mint,maxt)8 _, n |$ f( v% ^. ]6 n3 T
我修改为:" L" V, H i' x0 d0 p
[pn,ps1]=mapminmax(p);[tn,ps2]=mapminmax(t);
3 ^! ~0 y3 x, N0 Ca=mapminmax('reverse',an,ps2);$ F& `* n1 H3 r3 w
pnewn=mapminmax('apply',pnew,ps1);- I& j# C. C* Y1 {+ _1 w
anew=mapminmax('reverse',anewn,ps2)
2 {. ~6 b" T! M+ q, Q
4 R3 C* ~0 H, F9 S原程序为:
( {5 v! P3 b$ ~$ P%原始数据输入
) v9 Y( f8 V0 U8 ^. F, {2 mclc7 t. [- e/ \6 I& i6 `7 n
sqrs=[20.55,22.44,25.73,27.13,29.45,30.1,30.96,34.06,36.42,38.09,39.13,39.99,...
' B: v1 {; o( c 41.93,44.59,47.30,52.89,55.73,56.76,59.17,60.63];& I- _0 D- F9 O8 ~0 R3 g0 x
sqjdcs=[0.6,0.75,0.85,0.90,1.05,1.35,1.45,1.60,1.70,1.85,2.15,2.20,2.25,2.35,...# [- P/ R: i2 l4 J, M- v
2.5,2.6,2.7,2.85,2.95,3.10];
6 x5 X4 d! X3 |% K0 m. {( ?sqglmj=[0.09,0.11,0.11,0.14,0.20,0.23,0.23,0.32,0.32,0.34,0.36,0.36,0.38,0.49,...8 {/ E X6 S2 R3 u6 q$ [
0.56,0.59,0.59,0.67,0.69,0.79];
3 S, K# H4 a! `. ~7 p: Y) ~glkyl=[5126,6217,7730,9145,10460,11387,12353,15750,18304,19836,21024,19490,20433,...+ B/ a7 w& {) m
22598,25107,33442,36836,40548,42927,43462];4 ^3 r6 m! K# E4 s0 q) D0 W" @' A1 W
glhyl=[1237,1379,1385,1399,1663,1714,1834,4322,8132,8936,11099,11203,10524,11115,...
! v' S, P4 g- F6 A6 Z9 c 13320,16762,18673,20724,20803,21804];3 o4 X& Z5 _/ o6 ?$ H" A! k# Y
p=[sqrs;sqjdcs;sqglmj];* b! ^% m s3 L' y
t=[glkyl;glhyl];9 T, ]% E/ _, N1 H* q) H; J0 d0 F. U
- r+ \5 ^9 y- a" W& I" ^%数据归一化
5 P2 ~3 m8 q0 O; O- c[pn,minp,maxp,tn,mint,maxt]=premnmx(p,t);/ {& y. f% @6 Y, n+ @
dx=[-1,1;-1,1;-1,1];
! F. W: X# b- J7 w! D* G
9 a. E: g& K. X1 n%BP网络训练0 F# V5 n# o3 Q A4 }. L8 f
net=newff(dx,[3,7,2],{'tansig','tansig','purelin'},'traingdx');
5 n& I/ y4 \9 fnet.trainParam.show=1000;& ~; d; a; U, p
net.trainParam.Lr=0.05;; h& n- V; L2 U3 |! R* t4 b
net.trainParam.epochs=50000;
5 m3 J. V* b1 O5 f: }/ M& r" unet.trainParam.goal=0.65*10^(-3);- a2 F2 b4 t' x2 M7 w! S$ `
net=train(net,pn,tn);
7 B; ]5 \/ p' j# @1 e) F# V% g8 b: c7 H$ y& l5 W: R* d/ o
%利用原数据对BP网络仿真
% a) [! z* C7 N! wan=sim(net,pn);
: k4 |3 ?# ^6 b# t* U) W ]. P' b5 Ua=postmnmx(an,mint,maxt);, D6 j& H3 L; o ]* B0 I! y6 {
( t% E) e& {/ H. S/ K' @. i
%仿真结果与原数据对比测试6 a9 k' j/ Q" O2 x M! b
x=1990:2009;# b1 U0 X5 B: m4 l) ~7 P/ Y
newk=a(1, ;
, m; I! k! g& E" u# Vnewh=a(2, ;) e3 O$ x" K8 O; O
figure(2);
! H2 I3 W) J; S, I4 y2 asubplot(2,1,1);plot(x,newk,'r-o',x,glkyl,'b--+');
) J/ F8 C9 m0 j: O0 r; Olegend('网络输出客运量','实际客运量');
+ {4 s1 K' r5 {5 w$ M W4 R- Txlabel('年份');ylabel('货运量、万人');4 y$ R4 K5 ~( `& T+ j( {
title('运用工具箱客运量学习和测试对比图');5 ~9 e% f8 O6 r# ~7 p8 u
subplot(2,1,2);plot(x,newh,'r-o',x,glhyl,'b--+');
% a6 A: H& K' y# V/ o: i" klegend('网络输出货运量','实际货运量');- x% n( L3 M+ A4 r8 M" W) x
xlabel('年份');ylabel('货运量、万吨');
$ k8 g0 g- [ O. ?3 A1 Q2 Atitle('运用工具箱货运量学习和测试对比图');5 V* W( d) Q" p
0 R0 |, [+ Y$ G1 m2 U8 h
%新数据仿真
: S7 g2 b( m: l3 F0 c/ opnew=[73.39,75.554 w/ d9 q! Z# x* _1 p4 e
3.9635,4.09752 J& O2 \3 p1 s. G; O9 y2 F/ P6 ]
0.9880,1.0268];
8 I3 W) I: ]9 {/ `pnewn=tramnmx(pnew,minp,maxp);
: g6 Q! v$ ?& i9 v# m* ianewn=sim(net,pnewn);
2 R! y$ D a3 j2 Wanew=postmnmx(anewn,mint,maxt)
8 Z( V1 v5 A' A3 I; A' ?' D) c
% [ D- i) e* e" J8 ?1 h# H/ x) b修改后程序为:, V9 e) W$ Y) y
%原始数据输入- F6 ?; f6 Z& @) p2 j' r
clc
1 j9 [! L6 B" h" ]sqrs=[20.55,22.44,25.73,27.13,29.45,30.1,30.96,34.06,36.42,38.09,39.13,39.99,...$ M0 S1 v5 T) g& p
41.93,44.59,47.30,52.89,55.73,56.76,59.17,60.63];
3 f# }2 L2 i- K. [; U' E9 Ksqjdcs=[0.6,0.75,0.85,0.90,1.05,1.35,1.45,1.60,1.70,1.85,2.15,2.20,2.25,2.35,...
5 c: O* k- G: N6 @5 j$ |# \/ u 2.5,2.6,2.7,2.85,2.95,3.10];
, ~ @5 I/ Z5 k( D/ x2 P( [7 ssqglmj=[0.09,0.11,0.11,0.14,0.20,0.23,0.23,0.32,0.32,0.34,0.36,0.36,0.38,0.49,...- R- R3 a3 O% f
0.56,0.59,0.59,0.67,0.69,0.79];
/ h; m( p8 P) r# nglkyl=[5126,6217,7730,9145,10460,11387,12353,15750,18304,19836,21024,19490,20433,...
1 R3 S! z( S5 ^6 G 22598,25107,33442,36836,40548,42927,43462];& N" E+ N" J; a3 ?0 H4 W
glhyl=[1237,1379,1385,1399,1663,1714,1834,4322,8132,8936,11099,11203,10524,11115,...
. O, t: s4 K1 n 13320,16762,18673,20724,20803,21804];
4 ^9 l" X& q4 h) k# E! jp=[sqrs;sqjdcs;sqglmj];
8 D# L( t9 ~: k0 D. Zt=[glkyl;glhyl];/ A8 p" n8 O( @) v& L" R, L: d
9 k' @) e5 v0 W( j; ?: q8 I
%数据归一化4 i+ L! W5 Z' B
[pn,ps1]=mapminmax(p);+ D8 y1 K+ x2 M
[tn,ps2]=mapminmax(t);
; D' N( B6 v W/ ~* i5 `' U6 Q4 B7 W Z8 K
%BP网络训练
) P" w# C, o# s8 q3 hnet=newff(p,t,[3,7,2],{'tansig','tansig','purelin'},'traingdx');4 a. y- Y8 X4 D* W
net.trainParam.show=1000;5 i$ A3 P% T* t3 L7 [2 m! `7 m5 z+ S
net.trainParam.Lr=0.05;* g- t+ q- I9 T6 ?, b3 r6 u* e* D
net.trainParam.epochs=50000;+ v; J- O6 d4 A+ {
net.trainParam.goal=0.65*10^(-3);# U5 R6 g- H. s! ?* h9 l( h$ a
net=train(net,pn,tn);' _5 f- M$ j* V$ \5 Q
1 W' l% d% |. x8 R# N5 k% L9 g
%利用原数据对BP网络仿真, e: ^- l; M! B
an=sim(net,pn);
& \, {6 ?7 }: N2 o% n( F0 Ma=mapminmax('reverse',an,ps2);" s5 m, m5 ^# Q9 D1 E
0 p/ Y+ W6 Y! i _& B+ O
%仿真结果与原数据对比测试* e6 { r+ Q! s. o9 _' j
x=1990:2009;
; k* H4 ~0 _8 Z+ u6 Q4 H4 d, Unewk=a(1, ;& L+ l4 K b; N# ~
newh=a(2, ;
) I6 L$ c7 j% \1 ]+ F* i) |figure(2);) Q/ a, V+ S- @( H5 d3 d( @3 q3 v
subplot(2,1,1);plot(x,newk,'r-o',x,glkyl,'b--+');
+ l5 \7 c, D9 P1 t+ U9 V1 L! hlegend('网络输出客运量','实际客运量');
- y c) G- W2 [xlabel('年份');ylabel('货运量、万人');' N' w. ]# ~2 y$ G9 a7 M) z4 }: _
title('运用工具箱客运量学习和测试对比图');. w! G6 k0 x, d' R+ I% q# J
subplot(2,1,2);plot(x,newh,'r-o',x,glhyl,'b--+');
5 w4 p9 g, d+ Z1 ~8 Slegend('网络输出货运量','实际货运量');
: y& R% s6 F1 M. Qxlabel('年份');ylabel('货运量、万吨');5 ?* ?( W0 N' D3 p5 ~* N( R1 ~1 r
title('运用工具箱货运量学习和测试对比图');! ?& |: z% t6 i2 j- ?. h: M
- k- z5 I/ F" N2 V
%新数据仿真( q" Z' O$ p, i
pnew=[73.39,75.55: j6 m5 J: s1 t8 |4 M' {+ G& V; l8 y% |
3.9635,4.09754 l7 v# C7 t9 L$ |
0.9880,1.0268];' Q1 R3 S. L/ q# q- x1 R+ ]
pnewn=mapminmax('apply',pnew,ps1);
5 i+ ~; T- ~0 C% Zanewn=sim(net,pnewn);
0 F7 M T* E" k' B8 U1 ianew=mapminmax('reverse',anewn,ps2)
6 v' x# O. e+ c: T- S: x(修改的地方用颜色标记了)& k7 P5 D% c% S$ }/ R" W# `; k' n
麻烦您帮忙指出其中的问题,万分感谢! |
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