- 在线时间
- 1497 小时
- 最后登录
- 2017-5-18
- 注册时间
- 2014-8-20
- 听众数
- 160
- 收听数
- 0
- 能力
- 70 分
- 体力
- 17797 点
- 威望
- 5 点
- 阅读权限
- 150
- 积分
- 8920
- 相册
- 1
- 日志
- 0
- 记录
- 0
- 帖子
- 3830
- 主题
- 2802
- 精华
- 14
- 分享
- 1
- 好友
- 756
TA的每日心情 | 开心 2017-4-26 10:25 |
|---|
签到天数: 491 天 [LV.9]以坛为家II
- 自我介绍
- 即使不开心也不要皱眉,因为你永远不知道有谁会爱上你的微笑!
 群组: 数学中国试看培训视频 群组: 2017美赛两天强训 群组: 2015司守奎matlab培训 群组: 2016国赛优秀论文解析 群组: 国赛护航思路养成班 |
function [MVAbase, bus, gen, branch, success, et] =runpf- d: Q$ \) \, T( `' K+ P
[baseMVA, bus, gen, branch] = loadcase('caseRTS79');
( t" ?8 [) P6 A, `$ |" D2 {[i2e, bus, gen, branch] = ext2int(bus, gen, branch);
. L* s; ^5 b" g: v0 c3 j[probline,probgen]=failprob;) t! \& |& c+ j+ l: m$ M
[A,lpr,equ,Pgmax,goalA,busPg]=loadpro;3 k9 v# U3 b6 [1 G
w1 ], V! M1 _! O0 ?$ e( j( q
limB=zeros(1,48); %limB是1x48的全0矩阵; S# y4 I# z# d
ranbr=size(branch,1); %ranbr=矩阵branch的行数; p# a2 t7 f t* x
lineB=zeros(ranbr,ranbr); %lineB是ranbr x ranbr的全0矩阵
. Q$ y6 U# X( Z0 G2 Q( [2 Zfor i=1:ranbr %i从0到ranbr
2 W% I/ a! q$ S% x. w/ } lineB(i,i)=1/branch(i,4); %方阵lineB的对角元素分别是1除以branch第4列的相应行数/ `5 T7 K3 p4 G; I
end
; n# j2 }. }( C9 ZPload=bus(:,3); %Pload是取矩阵bus的第3列的所有元素
, }- P! R9 a0 G( ^' I$ h% CPload(13,:=[]; %删除Pload的第13行的所有元素
8 p1 O; V. l3 N0 `3 e' v6 @sumload=0; %定义sumload=0
b2 u4 X4 [# p) ufor i=1:size(bus,1) %i从1到矩阵bus的行数7 l" z' t" n& a+ w1 U
sumload=sumload+bus(i,3);
$ R8 r% M @. j3 J* lend %sumload=矩阵bus第3列所有元素之和
0 S N5 ~4 W0 o, |9 Isumpg=0; %定义sumpg=0 F( Y" W5 ^; X) D( R: S/ \( S
for i=1:length(busPg) %i从1到矩阵busPg的长度6 B- H# y. ?3 G& R* ~
sumpg=sumpg+busPg(i,1);
6 D& r; F+ o6 B7 Z, v, Jend %sumpg=busPg第1列所有元素之和
! r$ A& V8 u* e( K5 |# ~refPg=591-sumload+sumpg; ) u R7 h+ n, u
Pmax=branch(:,8); %Pmax是矩阵branch第8列的所有元素
5 f/ W$ C2 y! Y2 O/ T. \6 @1 [lolp=0; %定义电力不足概率LOLP=02 C$ A- C. y3 V; P9 h2 e( r/ o* D
edns=0; %定义缺供期望电力EDNS=0
7 l# @% r4 Y% y+ d: T* E9 @vari=0; %/ t+ C8 R' W& \: J# N+ Y9 `0 h
sumcut=0; %定义sumcut=0
. G7 A% B# V! L0 P2 K( L9 e. M# Gsumsqcut=0; %定义sumsqcut=0" B0 `7 X' v% T& A
B=[];( L* |% d2 j* y1 @: b
state=[];
+ `- W& S I5 G7 Y' ?for stct=1:50000
' `+ T# ?3 h* S8 q stvari=mc(probline,probgen);
3 E, o5 t+ u8 W# h5 d, G lengthst=length(stvari);
2 B+ O' S" k; {; Y! U6 T numstate=length(state);5 D* y2 k I {
lolp=lolp*(stct-1)/stct;' _+ ~+ Z% s/ w7 U0 i+ `* o
edns=edns*(stct-1)/stct;. Z0 j; S# L1 a8 W
ednsarray(1,stct)=edns;
8 d- g, G& ]+ h! ?# o4 C lolparray(1,stct)=lolp;' E7 _$ ?, D3 L W( N% [
- A7 d, G& j" i& w0 S if ~lengthst
& d9 x8 Y! r4 `- i1 ~ vari=sumsqcut-2*sumcut*edns+stct*edns^2;' [3 |6 s, i2 x$ S9 e2 B. C
vari=vari/stct^2;
2 Q0 Q9 t# O8 D- q& R7 @ vindex(1,stct)=sqrt(vari)/edns;
8 E p7 S2 M/ u3 y3 t ednsarray(1,stct)=edns;' ?1 |# {- u u5 L8 ^
lolparray(1,stct)=lolp;
! ]$ Q* I! C1 g" S9 ~4 K9 v continue;
: l0 z' n# D4 ~% e8 | else
. ]: t) I+ i& [. O* ?7 L: r flag=0;& L$ h; }4 H$ v* g- Q3 F
for k=1:length(state)+ L; J7 _% p( o" _, @% h; t% a N
if lengthst==length(state(1,k).st);( [ i* o' [7 A6 S9 V, Z+ X
if stvari==state(1,k).st
$ C! J0 u" Z& |2 k state(1,k).num=state(1,k).num+1;( P4 t6 \+ z9 A) r
flag=1;
& x$ u; @9 W9 q; O' w2 C2 D break;
: l9 j% L; U: a end% N1 Q0 ?" Q0 p( f% g6 l+ r
end
e4 J l; p5 x, z' c+ s v( | end" l0 j. j0 k# l& \ q% ~4 H
if ~flag
* h5 e) K1 P( b; u5 W6 J state(1,numstate+1).st=stvari;
, e( {# |" |0 A. n state(1,numstate+1).num=1;
5 ]. D) T8 d% G+ ^$ c( ~% U: T; z end
. ^8 e- n& \: a end& c$ ?! T- s7 \5 F- t+ f' K' k- ^4 F
if flag
; a2 ~; q) Q9 ?4 [& |) E! Q* [" O B if state(1,k).cutload
0 G" ?* d* d2 p ?3 m: s8 s sumcut=sumcut+state(1,k).cutload;
. `9 B4 R* {# w7 X3 E$ Q* H sumsqcut=sumsqcut+state(1,k).cutload^2;
6 p& |$ V q4 e5 U lolp=lolp+1/stct;; @# y$ n! y6 d4 x7 w+ @
edns=edns+state(1,k).cutload/stct;
5 C: G. A* R; l( _. }' R9 G vari=sumsqcut-2*sumcut*edns+stct*edns^2;- D8 ^4 Z" G" {
vari=vari/stct^2;6 Q) ~4 |- S! O" O7 s2 P
ednsarray(1,stct)=edns;: | b+ G* U/ ] j7 M% m& m
lolparray(1,stct)=lolp;
8 k! N u' X2 E U end
9 P# R0 i" s P" n7 z; u* |1 d vindex(1,stct)=sqrt(vari)/edns;9 S* x/ O) `% K* m1 ^- E4 [
continue;
+ E2 F9 H% B" a G end
1 I3 D, B" \; ?; j7 N clear stvari;
?8 [! c, ^4 G6 H8 b. B4 k
( F. f5 V. {7 N" B1 b. p ischange=0;
$ o$ {9 V9 I- ^ sPgmax=Pgmax;( p0 A! d K) h# r, [
sbusPg=busPg;
, `6 x4 |# w& W# M* I srefPg=refPg;
3 b- {5 l5 u' m8 }% i9 _ outbr=0;
# t2 {4 i) N& h' p outgen=0;
% H! m% q p# D- K8 A) x5 x for lenct=1:length(state(1,length(state)).st)$ m7 ?, Q8 |$ {* |
if state(1,length(state)).st(1,lenct)<39, z$ D, M8 q" ]0 k
outbr=outbr+1;
9 J/ ?% q6 O9 d& K6 \& f branch(state(1,length(state)).st(1,lenct),11)=0;0 F; D" D7 |: C: }0 ~( P
memobr(1,outbr).loc=state(1,length(state)).st(1,lenct);9 [ [$ a# x& M8 E
memobr(1,outbr).b=lineB(state(1,length(state)).st(1,lenct),4);
& O- g7 C f# i3 T lineB(state(1,length(state)).st(1,lenct),4)=0;9 L! } \% W/ s: g" Z
ischange=1; [. e$ I2 A8 N" d4 p3 N l0 M
clear B;
# C& a9 {/ F% p5 h, B d) U / S$ n/ {6 b/ x2 n
else
5 R0 W6 B% F- }0 R: } gavri=state(1,length(state)).st(1,lenct)-38;
/ Z- j0 f) P3 G/ Y2 n3 r gen(gavri,8)=0;
' [1 x! E& A2 U9 C. l srefPg=srefPg-gen(gavri,2);
$ ]' v+ J/ z8 ~4 f; t outgen=outgen+1;
' M3 m7 C$ I" I8 M& d, Y memogen(1,outgen)=gavri;' b0 C# m% ^+ r; ^
if gen(gavri,1)<13" I) r( X8 W* c( Q8 y( w- Y3 |
sPgmax(1,gen(gavri,1))=sPgmax(1,gen(gavri,1))-gen(gavri,9);
0 L2 B5 M& |3 W- D9 Z v sbusPg(gen(gavri,1),1)=sbusPg(gen(gavri,1),1)-gen(gavri,2);
' D: r% o2 p$ F end
! d3 v5 Y) c1 G8 F7 `* y1 I, k if gen(gavri,1)==13
% u' M8 k1 o0 z$ ]- N srefPg=-1;8 I7 y: I2 A' X; m0 q4 P
sPgmax(1,24)=Pgmax(1,24)-gen(gavri,9);1 x+ B f9 c+ [. ^8 D8 U
end# b0 }9 d1 f3 r$ y/ ~; n
if gen(gavri,1)>13
$ w$ Y3 a( i* ~9 W u5 _ sPgmax(1,gen(gavri,1)-1)=sPgmax(1,gen(gavri,1)-1)-gen(gavri,9);
, q- v: K. D" P3 R sbusPg(gen(gavri,1)-1,1)=sbusPg(gen(gavri,1)-1,1)-gen(gavri,2);1 n) p0 A! Q+ {0 Y
end
& f8 a, \8 w/ P1 N# Z, f3 t end
3 @# B' H0 `! O% S$ u end
3 ]4 U! D+ w1 Y3 ]& v3 L% if (stct==1)|ischange
. s% d2 L' k1 J1 @ B = makeBdc(baseMVA, bus, branch);5 f* z' u5 h3 j: S
subB=full(B);
6 N# s" P. p- \& H. ~. E subB(13,:=[];2 j5 a; G7 |5 s& R7 B9 k
subB(:,13)=[];
8 r9 h3 e4 z. L4 V- k6 P; L1 ?& ` swp=lineB*A*inv(subB);
1 i8 u5 t- B* V swp1=swp*Pload;
: X j" R# k/ m! J! Y2 M maxArray=Pmax+swp1;7 d0 d+ h: t* i6 Q
minArray=swp1-Pmax;: K2 B6 V4 F; M
maxArray=[maxArray;-minArray];
( c+ \/ d3 q$ g# @* A4 F lprA=swp*lpr;) e* l/ J: a0 C" L& M# A( A* i# g
lprA=[lprA;-lprA];( S1 }2 n; u- e- x+ V( s
clear minArray- J. F6 Y) R0 U, P: d4 e5 |( n% `
clear B B" o5 E0 u) @/ T9 N" v$ n
clear subB) s0 c6 U }" i- |. g3 ~
% end
) G' ^' N' @9 e L1 t' ~ " b3 w0 z" Z3 L7 j* i0 I K
state(1,length(state)).cutload=0.0;
" b$ W3 d2 C5 @7 L% h if srefPg>0
( R- X0 j% G' h: }% l brflow=swp*(sbusPg-Pload);" n. h! k9 I Y8 U3 Y/ ~
cutload=0;4 n- F! b2 R' H4 k! O. v3 S' ]
for ctbranch=1:38
: V3 O: p9 g3 V% I' Q, w if abs(brflow(ctbranch,1))>branch(ctbranch,8), z( Q0 v* M/ W( p2 a8 o2 k
limA=[Pload',bus(13,3),sPgmax];$ l$ e( m# r0 ^/ [* S' ~
[m,cutload]=linprog(goalA,lprA,maxArray,equ,sumload,limB,limA);
; q* V. e0 I) a if cutload>1: [% ?/ s+ F. L( H' T5 d
state(1,length(state)).cutload=cutload;6 K8 z7 b/ o3 f, n, k5 J
end: e- n/ e, E3 e% T6 m/ Z
break;
5 y) C2 ]: i0 } } end$ O9 @: E, _3 R0 G' }/ w+ I& }
end
) W- h, ?# b+ N7 p5 @& J, V' U else. V& \! T/ F0 f) i& X! R
limA=[Pload',bus(13,3),sPgmax];( W: H- P4 c8 m2 t
[m,cutload]=linprog(goalA,lprA,maxArray,equ,sumload,limB,limA);
# L6 f) V; Z7 q* N. i2 ] if cutload>18 y# F E1 a0 P) f! {
state(1,length(state)).cutload=cutload;& E8 x% i4 K. T1 E1 b. ~
end
\/ k, Y" s- R end
9 g0 i& u; ~, s$ g' C3 t/ W5 o if state(1,length(state)).cutload
- y( l; E1 N: N$ Q sumcut=sumcut+state(1,length(state)).cutload;; |8 ]: {6 U0 ^+ l
sumsqcut=sumsqcut+state(1,length(state)).cutload^2;' Z3 o( F2 u( t0 f ]% B& c
lolp=lolp+1/stct;7 o$ z' d" I, B P8 F* l
edns=edns+state(1,length(state)).cutload/stct;6 a C# q' R/ H2 N V4 v
vari=sumsqcut-2*sumcut*edns+stct*edns^2;' l9 K' ?4 n; B( K$ |
vari=vari/stct^2;
7 j: _% B9 E" g, N( b ednsarray(1,stct)=edns;
/ {6 `! O& X9 s7 K- H- `0 s lolparray(1,stct)=lolp;
9 t8 r$ H0 K& o' g( l! T4 W& I end% F, x, z9 X& u% j& k5 Z
vindex(1,stct)=sqrt(vari)/edns;
: d+ m% O% w9 L! D; n4 L+ B success = 1;" K0 x+ y4 z8 N& {! n
for i=1: outbr( L3 f: w% F7 k
branch(memobr(1,i).loc,11)=1;2 A8 E4 k6 a) n2 j
lineB(memobr(1,i).loc,4)=memobr(1,i).b;
3 b& B- t) l0 R) u end( ~1 ]6 V0 z! y% {0 P! O: H
for i=1: outgen
2 d% U; j0 B, [4 t gen(memogen(1,i),8)=1;& i# G5 e) ]3 E- M. M' G4 t& v
end
7 J. v: p4 ^" m clear memobr;
% G: n! c D" a Z/ D5 {, k clear memogen;
6 y" C& ~+ l' \! P. W0 W8 G- Y- A* T% if (stct>10)&(vindex(1,stct)<0.017)& q1 B% W# r* P3 f
% break9 @4 p1 ?0 Z# h2 p' Y+ w3 B* a
% end- c$ Z, g$ I! i1 a* A A& s
end
- ?) W5 ?0 O2 B8 hlayer=zeros(1,15);
: Q" Y1 o) Z& z2 ^: \, Ufor i=1:length(state)
; H7 V( E2 ]- r1 y$ @0 o4 x, k0 D layer(1,length(state(1,i).st))=layer(1,length(state(1,i).st))+state(1,i).num*state(1,i).cutload/stct; Q! G$ M: v0 i5 N6 d( O
end& }* O# _. @3 l" x) L3 @1 ~
9 q! k8 ], h \7 v( Nlolp
! q! c0 }9 o0 U; _4 xedns
1 W8 i+ C! m; \3 O+ H+ I# Zdlmwrite('E:\study\edns1.txt', ednsarray);
1 I D+ g& `6 m fdlmwrite('E:\study\lolp1.txt', lolparray);% s3 M2 j, S; X( W2 K7 \( `: c
dlmwrite('E:\study\var1.txt', vindex);9 L/ F, C, ~! u3 @1 w2 T1 ?* w
dlmwrite('E:\study\layer1.txt', layer);
5 j1 j" s9 {7 O) l9 R' pplot(vindex);' w; ?9 Q/ P( `2 `/ j
hold on
5 j1 G9 g, s( k; T* s( aplot(layer)
9 J, |& H* z: ~) r" greturn;
% r7 m8 w$ ~7 l7 d/ _! A- W5 @6 Z- _0 K# l& p2 F
rudeMC.rar
(18.16 KB, 下载次数: 8, 售价: 2 点体力)
| 9 V) U" c3 ^, `- U
" u3 V1 d) E" @6 n
4 d! P$ ?9 Z6 O" X4 W& c; Y- B
; O. \5 F9 p) K S# f
|
zan
|