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发表于 2009-8-16 18:59
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修改一下循环的下标可以使得程序编译通过,但是不知道是不是和你的模型相符合,你仔细分析一下吧!
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- model:6 c; i9 o Z& v& T' s# X
- !n个货车8收点运输问题;
% v/ n, x4 a6 y1 T1 r' g - sets:% r2 _; F/ u' y; L6 B2 d1 o
- place/place1..place10/:time1,time2,timexie;4 Y8 e7 `3 ^& m6 t
- car/car1..car3/:time;7 P5 t6 b- ?# P\" i3 e
- * O! K6 I9 n3 ?7 ]/ Z; q0 @# @$ M% {
- jiu/1..9/;) T' ]; w6 k8 Y. g. W& b
- er/1..2/;* Z( F. T2 y. p6 `0 g8 p9 y
# ~& J! t3 _5 K Y- lc(car,jiu):lucheng,ct;
8 `* z6 ?& k) t' u' \, }# c - plan(place,place,car):a;* \; n$ e s! l0 q( h
- distance(place,place):dd,dt,which;* o: g- b$ {\" I& e% \ ~
- endsets- [7 J5 z6 T) Y) L% ^+ D* u; f
- ) E* i1 K3 ~' ^5 T2 d5 _7 {4 U
- 2 c9 c$ ~# l$ O/ q- m p
- !这里是数据;; l2 V$ |0 t% D( ^9 K; [9 o
- data:# z% d9 m8 y2 \! r9 k- Y
- s=1;
6 W4 _2 A1 p. S. q$ K - time1=-10 1 4 1 4 3.5 2 5 1.5 1;
9 x. @5 \8 q* m: z* ~ - time2=7 4 6 2 7 5 5 8 4 10 ;; c* ^+ g; X1 e
- timexie=0 1 2 1 3 2 2.5 3 0.8 0;% q/ k* m' o: o
# Y( [' R' t) m6 s0 C& p0 @ n- , c# f# @5 S8 d3 X: e9 F
- dd=1 ?& E, w( [5 Z* k7 w; w4 L
- 0 40 60 75 90 90 100 135 80 0. u0 ], \8 V\" [+ Z/ f0 J4 v0 a8 o! M! Y
- 40 0 65 40 100 50 75 110 100 40
+ j1 M \/ A\" _; l6 C6 m2 A4 O - 60 65 0 75 100 100 75 75 75 60: A8 m7 ~* M* ^% M
- 75 40 75 0 100 50 90 90 125 75& J A c7 d1 l) R
- 90 100 100 100 0 100 75 75 100 90& Y$ Q' B6 [3 e6 E1 [7 g* R$ @
- 90 50 100 50 100 0 70 90 75 907 H2 j1 p! A! ]& ?* \
- 100 75 75 90 75 70 0 70 100 100
; k+ T9 l2 Z+ D8 q1 f& Z - 135 110 75 90 75 90 70 0 100 135
7 d7 k6 Y: I2 s+ s+ [ - 80 100 75 125 100 75 100 100 0 809 U. B7 a\" p; q: u8 O! M: r
- 0 40 60 75 90 90 100 135 80 0 ;
) [3 h k, {6 l2 } - dt= 0 0.8000 1.2000 1.5000 1.8000 1.8000 2.0000 2.7000 1.6000 0
b0 }) P1 M( \- V - 0.8000 0 1.3000 0.8000 2.0000 1.0000 1.5000 2.2000 2.0000 0.8000\" m$ U7 O% \* ~* D1 M8 k
- 1.2000 1.3000 0 1.5000 2.0000 2.0000 1.5000 1.5000 1.5000 1.20006 o( V& H4 m6 T& m\" _
- 1.5000 0.8000 1.5000 0 2.0000 1.0000 1.8000 1.8000 2.5000 1.5000
/ O5 {\" Y6 g n( q6 _ - 1.8000 2.0000 2.0000 2.0000 0 2.0000 1.5000 1.5000 2.0000 1.8000. z4 }6 G: u& i: x% _0 Z
- 1.8000 1.0000 2.0000 1.0000 2.0000 0 1.4000 1.8000 1.5000 1.8000
8 y/ Y% d5 k( h6 x$ f - 2.0000 1.5000 1.5000 1.8000 1.5000 1.4000 0 1.4000 2.0000 2.0000
R7 d) ]6 j$ V. B/ Y) q - 2.7000 2.2000 1.5000 1.8000 1.5000 1.8000 1.4000 0 2.0000 2.7000
4 J: W9 a! S7 v5 a\" J% b - 1.6000 2.0000 1.5000 2.5000 2.0000 1.5000 2.0000 2.0000 0 1.6000
2 ~+ x( ^7 n# C1 @3 Z) M, k - 0 0.8000 1.2000 1.5000 1.8000 1.8000 2.0000 2.7000 1.6000 0;( f ~. J$ N& b5 G8 W
- enddata
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: t4 S# K4 K/ d. R- !目标函数;
9 v8 n4 [\" b8 p4 Q - min=@sum(lc(I,J): lucheng(I,J));, |6 ]# T L8 X2 D7 \9 M& r7 }
- , Q% w: b9 I m
- !整数约束;; ]( S\" C' F. ~$ n
- @for(plan:@bin(a));
: n$ Z+ J9 C; q. X - @for(car(I):@free(time(I)) ;5 D1 J! K3 g6 X1 V7 Y
- , Y+ F2 S2 U, ?. ?0 i. Q
- !从零点开始最终回来;% I* o. j: x1 N& \1 r$ M
- @for(car(I):; ?$ N* p7 y7 p: T+ E
- a(1,1,I)=1;a(10,10,I)=1);
* \' D. H s) c9 ~
\" T) F* R* \8 t7 ~* i7 N- !每个任务只能有一个;
! U/ U) N! h4 u1 y& l - @sum(car(I):0 [7 {/ I/ P! s; q
- @sum(place(K):& F8 m6 [% R2 @\" t3 S. d
- @sum(place(J): a(J,K,I))))=1;( H6 G* I+ i$ q; O! m9 F
- - B: a7 t2 M\" f# }' O+ a) w
- !每个车的任务最多有四个;8 @7 L, M( q }4 i
- @for(car(I):
4 F2 H3 D, F6 ?5 p$ R4 h; O0 K - @sum(plan(J,K,I):a(J,k,I))<=6);7 o+ t8 |5 M- s
' `, Q' P3 U c' u5 ~* c- !前一辆车任务大于等于后一辆车;
( N+ A7 L' N2 y# O6 A\" w - @for(car(I)|I#lt#1:
* r3 `( s4 [* F+ r - @sum(plan:a(J,K,I))>=@sum(plan:a(J,K,I+1) );
' q4 Q/ h- R. s
/ u- b# i+ Q' ? b' e! N! T- !求which 例子 若a(1,:)=[1 0 0 1 0 1 0 0 0 1];
0 T, M2 G# e+ O2 p; V1 m7 f - ! 则 which(1,:)=[1 1 1 4 4 6 6 6 6 10] ;
9 ]: L; {) z8 V1 R' i5 q1 q - @for(car(I):
4 B1 t+ B* Z6 K - @for(place(kk)|@sum(place(jj):a(kk,jj,I)) #eq#1:
5 T, N\" s! `/ |5 p - @for(place(jj)|a(kk,jj,I) #eq#1:9 C) v7 F r/ k3 i* Q+ z& @! I: u* k$ N
- which(I,kk)=jj ););, `+ P2 T+ g. L: j+ l
- @for(place(kk)|@sum(place(kk):a(kk,jj,I)) #ne#1:6 v1 R\" o5 d; ]4 P$ m
- which(I,kk)=which(I,kk-1));# E) I# C- s1 t) f+ [. C
\" B* p6 ~) v* a- !时间限制;( N+ K& W) K' P% n Q
- @for(car(jjj):/ n9 y1 {\" g7 s4 j3 o& b+ b& m
- time(jjj)>=-10;time(jjj)<=7);0 Y- @* a% A0 Q f; t6 Z
- * p% w; M8 a# q* y
- @for(jiu(jjj):8 T9 B' b& f$ z3 E& S& j) D
- ct(I,jjj)=@if(which(I,jjj)#ne#which(I,jjj+1),dt(which(I,jjj),which(I,jjj+1))+timexie(which(I,jjj)),0)); ~3 v/ P' C9 r4 g7 p5 ?4 b
9 A( |9 P I1 X# W+ {+ P g( w- @for(jiu(jjj):! x; m! ^! ]5 [# S4 J0 m/ J. z' ]9 q
- time(I)+ct(I,jjj)>=time1(jjj+1);time(I)+ct(I,jjj)<=time2(jjj+1));
# J: O( m+ Z# \* t! |$ Q7 P! a - # b) E4 ] N# A
- !求每辆车行驶的距离;
, K$ s; w+ T# f) E2 n - @for(jiu(jjj):
2 `& ?$ b# P8 S3 `* m - lucheng(I,jjj)=@if(which(I,jjj)#ne#which(I,jjj+1),dd(which(I,jjj),which(I,jjj+1)),0) );- @3 b z% P$ u8 }# G; \. G2 ]' K
- );););5 C+ `5 i+ {0 \5 x3 J
- end) W( P- L% t( f% [+ E( Y: J6 |
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