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发表于 2009-8-16 18:59
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修改一下循环的下标可以使得程序编译通过,但是不知道是不是和你的模型相符合,你仔细分析一下吧!
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0 {8 e9 j& |- v- model:
9 b; q' E S! a4 {: T. T* B1 _( ? - !n个货车8收点运输问题;7 k+ F) U) T, p8 A
- sets:
/ Z\" ~7 ^# H3 A# H8 a2 K: u+ I$ a/ E - place/place1..place10/:time1,time2,timexie;
4 Z5 c; N- l: B5 N - car/car1..car3/:time;8 t+ i/ a: c& O7 n9 ^7 L' Z
- 7 B9 }8 l) [' E' B8 ^
- jiu/1..9/;! c+ L) K' c0 V* ~- v: G+ w
- er/1..2/;
+ k/ K: z/ L2 i3 k\" q
. l: @. I- f# z; P5 f1 ^- lc(car,jiu):lucheng,ct;/ F( M0 B! g# n% F5 P
- plan(place,place,car):a;
+ W4 s8 [: F) U - distance(place,place):dd,dt,which;) ~( m# W' ^4 s& n8 o
- endsets0 ?3 Y7 _\" h) x\" Q6 h' J D% r7 n
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- !这里是数据;* _- y; n8 E( D2 R2 A
- data:
# i; k4 s3 a+ `. g5 F - s=1;
# N) l/ P9 u& X - time1=-10 1 4 1 4 3.5 2 5 1.5 1; 8 ?8 C) @$ S; b
- time2=7 4 6 2 7 5 5 8 4 10 ;- ]4 |; t7 t L- {& W
- timexie=0 1 2 1 3 2 2.5 3 0.8 0;. G' H\" y& H5 I
- \" j- A+ Z& k1 N G7 c( A$ Z
4 Y; }/ U$ L/ D& d9 O- dd=' m, a7 {) S# D, O1 M
- 0 40 60 75 90 90 100 135 80 0( j! t\" }8 J\" |4 @ l
- 40 0 65 40 100 50 75 110 100 402 @& l0 L j ^# R9 o8 _% o! \$ p
- 60 65 0 75 100 100 75 75 75 60
( m8 A0 D; a9 v) V0 M+ B% \ - 75 40 75 0 100 50 90 90 125 75
3 Z2 w% c8 f* G. p. S, n/ `5 c& i - 90 100 100 100 0 100 75 75 100 90
$ x1 L. w9 I L4 J* k! k( w X. } - 90 50 100 50 100 0 70 90 75 90, J6 @- R+ L) ]4 |2 A- J
- 100 75 75 90 75 70 0 70 100 100
# ?$ E. K1 R% h/ ~3 z$ T& L t - 135 110 75 90 75 90 70 0 100 135
5 H0 e\" z+ J; u% L0 M - 80 100 75 125 100 75 100 100 0 80/ }% p2 P9 [4 |& c% p; Y
- 0 40 60 75 90 90 100 135 80 0 ;\" @: ~# h% {\" n* {& l* b' m- |' S
- dt= 0 0.8000 1.2000 1.5000 1.8000 1.8000 2.0000 2.7000 1.6000 06 i/ v6 P( _# e' R. t
- 0.8000 0 1.3000 0.8000 2.0000 1.0000 1.5000 2.2000 2.0000 0.8000
, w, d3 V: d\" S- I1 `) v7 | - 1.2000 1.3000 0 1.5000 2.0000 2.0000 1.5000 1.5000 1.5000 1.2000
. x0 o* p4 j m7 ~\" \7 t - 1.5000 0.8000 1.5000 0 2.0000 1.0000 1.8000 1.8000 2.5000 1.5000+ C1 v- T# Z2 M- i4 u
- 1.8000 2.0000 2.0000 2.0000 0 2.0000 1.5000 1.5000 2.0000 1.8000! A. a. ?- T) }! i. i6 F
- 1.8000 1.0000 2.0000 1.0000 2.0000 0 1.4000 1.8000 1.5000 1.8000
n* \2 l# Q2 P8 i5 T' M( A5 \ - 2.0000 1.5000 1.5000 1.8000 1.5000 1.4000 0 1.4000 2.0000 2.00002 E0 Y- t+ h; R7 r& G9 B' ?, ?
- 2.7000 2.2000 1.5000 1.8000 1.5000 1.8000 1.4000 0 2.0000 2.70002 o5 X, M9 D- B- c1 Y
- 1.6000 2.0000 1.5000 2.5000 2.0000 1.5000 2.0000 2.0000 0 1.6000
) G\" _( I* D4 d0 G9 L9 ^ - 0 0.8000 1.2000 1.5000 1.8000 1.8000 2.0000 2.7000 1.6000 0;
+ @- B4 p: a4 e- d+ Y+ N - enddata\" m2 {\" N% t5 r' g s, R
6 Q. }4 n. U0 P5 Q/ x& z0 P: [
- z0 M5 D( r1 q' l\" d: V) @- !目标函数;
$ Q$ U1 t0 q9 k+ p - min=@sum(lc(I,J): lucheng(I,J));
; P$ R1 y l0 O - % C2 s: e* i8 Q/ C5 Z; c9 \
- !整数约束;7 u5 ?. \8 U/ F\" _ I3 K
- @for(plan:@bin(a));2 n) m0 ^9 `$ O# o
- @for(car(I):@free(time(I)) ;
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& G+ u8 U/ H! u7 N- !从零点开始最终回来;
2 v$ u3 S+ d; F1 A - @for(car(I):7 v( d2 v5 G7 K9 M# W: z( c
- a(1,1,I)=1;a(10,10,I)=1);* n+ Q6 J% T+ O
- + ]# d9 A f7 V: _# x6 U7 W& |
- !每个任务只能有一个;: `* q) o& E5 G# G
- @sum(car(I):
8 `( H4 @% { X - @sum(place(K):
9 q! q5 L; e4 T\" v: Z - @sum(place(J): a(J,K,I))))=1;
3 z/ X$ j! Y+ {- \ - 8 e% H; s6 N; B3 U i5 \) J
- !每个车的任务最多有四个;
2 J) ~% M' \% @6 I6 }% J3 j7 i; S: q4 g0 K( g - @for(car(I):0 J0 k3 m. O' h8 u! i) ]7 {$ V1 R
- @sum(plan(J,K,I):a(J,k,I))<=6);
- E- p+ G5 [% m$ ]! J8 X3 `
! A4 T( o% D8 h0 h; M- !前一辆车任务大于等于后一辆车;% ?& S! t B) v
- @for(car(I)|I#lt#1:
V2 {; a, T6 C/ I7 B - @sum(plan:a(J,K,I))>=@sum(plan:a(J,K,I+1) );5 c! c2 I- P U
& a5 c# g7 i& e, w5 P5 M) o, f- !求which 例子 若a(1,:)=[1 0 0 1 0 1 0 0 0 1];
! m6 Y9 _% l6 M0 v9 y8 W1 C - ! 则 which(1,:)=[1 1 1 4 4 6 6 6 6 10] ;
4 B\" S M+ m5 }7 [ - @for(car(I):
0 g9 s e8 t\" m6 q( S$ \+ d4 Z3 g - @for(place(kk)|@sum(place(jj):a(kk,jj,I)) #eq#1:
1 w3 D, \/ s% W0 [! {. P - @for(place(jj)|a(kk,jj,I) #eq#1:
8 i3 ~' [4 _8 v' J, u3 J - which(I,kk)=jj ););' V\" O: A# J) }4 j7 O6 ^
- @for(place(kk)|@sum(place(kk):a(kk,jj,I)) #ne#1:% U o5 f- k- ^+ h2 R
- which(I,kk)=which(I,kk-1));- J1 m0 g l2 y! N' s$ b& N* u9 Y
- 2 k6 f @# v\" j, u7 P: c+ E5 l
- !时间限制;
1 E. Z& H3 q _. R - @for(car(jjj):
, d* w# m7 ~3 T( g - time(jjj)>=-10;time(jjj)<=7);
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6 a7 E7 }; R* p, v- @for(jiu(jjj):, L1 T+ W6 a$ U. g4 w8 i( D6 X
- ct(I,jjj)=@if(which(I,jjj)#ne#which(I,jjj+1),dt(which(I,jjj),which(I,jjj+1))+timexie(which(I,jjj)),0));
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8 A1 P! Z' m. K* H2 y' }- t/ k, W- @for(jiu(jjj):
! W+ X% k* f) v0 r - time(I)+ct(I,jjj)>=time1(jjj+1);time(I)+ct(I,jjj)<=time2(jjj+1));
) `. v# Y' V5 v9 z, q3 \ - ; X& K; S$ v0 x/ n; t7 b
- !求每辆车行驶的距离;
9 |2 n0 F, q* y0 P - @for(jiu(jjj):
' ?0 x$ I1 C) O, C* C - lucheng(I,jjj)=@if(which(I,jjj)#ne#which(I,jjj+1),dd(which(I,jjj),which(I,jjj+1)),0) );
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- end
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