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发表于 2009-8-16 18:59
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修改一下循环的下标可以使得程序编译通过,但是不知道是不是和你的模型相符合,你仔细分析一下吧!
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- model:
1 W7 L1 @$ ~0 w! `! m$ [ m - !n个货车8收点运输问题;( A5 c+ R! @3 Z\" E2 l$ S6 a
- sets:
/ D/ ?7 Q2 \9 Q& R E, d - place/place1..place10/:time1,time2,timexie;
6 C5 ]: a5 C2 u - car/car1..car3/:time;9 \- p( _ [4 O
0 x8 @/ U7 }/ E% _\" k- jiu/1..9/;6 [9 ]: h- z$ P2 f b3 V
- er/1..2/;+ G7 r/ y, G7 U\" Z2 g) r3 B
- 5 g: A4 m+ q8 U3 E
- lc(car,jiu):lucheng,ct;
y' u- p; h* G; n1 G! N. L - plan(place,place,car):a;
9 S0 I X, y/ }) b# ?0 G, i - distance(place,place):dd,dt,which;
' s/ \) @; S1 }' s; o\" B - endsets
1 T) ?, h* u \\" n2 e0 E' } {
* c5 q3 i1 B1 h\" J1 X- 5 d4 J: R- k) D/ ~
- !这里是数据;' }8 O1 R4 u6 I# _
- data:
% Y\" `. v$ k2 t6 x Q0 f - s=1;
( C4 a2 R5 ^3 s) r1 V - time1=-10 1 4 1 4 3.5 2 5 1.5 1; 8 N5 G- ?3 R! M$ v! A( c9 g- A
- time2=7 4 6 2 7 5 5 8 4 10 ;0 B( b- S! ~) g& H
- timexie=0 1 2 1 3 2 2.5 3 0.8 0;
* C I& Q( L7 [$ m F5 n, ?. u
' N' K/ Q; s3 C4 T+ z7 @) i5 [! _) p
- S) m6 ]7 k. F\" S% Y- dd=- b! Y6 a' X4 {- J% \
- 0 40 60 75 90 90 100 135 80 0
. z: W m9 L5 B - 40 0 65 40 100 50 75 110 100 40
) R: ^3 J7 a4 X7 g - 60 65 0 75 100 100 75 75 75 60
7 Q- ?7 W0 x# }- q, G - 75 40 75 0 100 50 90 90 125 75% V: }. T6 l* T1 s7 M2 r
- 90 100 100 100 0 100 75 75 100 90
6 z; R7 E3 v& N+ G' p( C4 P* O& i9 B# t - 90 50 100 50 100 0 70 90 75 90
x O; q, Z' S% J n6 o1 N* ] - 100 75 75 90 75 70 0 70 100 100
, w/ I\" ^9 ]% ] G A! W\" W - 135 110 75 90 75 90 70 0 100 135# D3 O- u. \\" h$ K( i: p4 @. |
- 80 100 75 125 100 75 100 100 0 80
7 o0 U; ^2 _; t. e( O2 j5 v - 0 40 60 75 90 90 100 135 80 0 ;! B: ^% L# w# d. c
- dt= 0 0.8000 1.2000 1.5000 1.8000 1.8000 2.0000 2.7000 1.6000 0* e2 \' N. L8 a* w7 _! l
- 0.8000 0 1.3000 0.8000 2.0000 1.0000 1.5000 2.2000 2.0000 0.80006 T+ g K5 b0 @+ d6 e\" y
- 1.2000 1.3000 0 1.5000 2.0000 2.0000 1.5000 1.5000 1.5000 1.2000
\" q. T$ ^) a; e/ q7 i2 A1 u6 d k8 N - 1.5000 0.8000 1.5000 0 2.0000 1.0000 1.8000 1.8000 2.5000 1.5000& B+ l; V c* \4 x8 B\" q# N
- 1.8000 2.0000 2.0000 2.0000 0 2.0000 1.5000 1.5000 2.0000 1.8000
6 p1 N\" h: p7 H0 z6 M+ k( Z$ h - 1.8000 1.0000 2.0000 1.0000 2.0000 0 1.4000 1.8000 1.5000 1.80005 y0 [8 T+ }\" s3 O: V4 b
- 2.0000 1.5000 1.5000 1.8000 1.5000 1.4000 0 1.4000 2.0000 2.00007 U. e, S T\" x3 [8 o2 e
- 2.7000 2.2000 1.5000 1.8000 1.5000 1.8000 1.4000 0 2.0000 2.70003 k( y% M! V; A+ L
- 1.6000 2.0000 1.5000 2.5000 2.0000 1.5000 2.0000 2.0000 0 1.60000 X R; y2 r# o4 B0 l
- 0 0.8000 1.2000 1.5000 1.8000 1.8000 2.0000 2.7000 1.6000 0;
- A: V1 a* ?2 }4 e& X' F - enddata% W0 g4 H8 }; w+ a
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- !目标函数;, Z2 U! w' ^- f* ^: w
- min=@sum(lc(I,J): lucheng(I,J));# i5 l- d0 ?9 S3 H/ O; G2 r
- ! ^5 f6 I, I\" Y* {. p+ I
- !整数约束;
/ c\" R. d% ^' A4 C9 D' A - @for(plan:@bin(a));. i* n# i2 }/ ]
- @for(car(I):@free(time(I)) ;- {8 K9 J- ?1 ]0 i1 ?- t9 O
- : q C: r* f! ^* z) `: k3 M0 }7 I3 A
- !从零点开始最终回来;/ [8 i( }3 a& K7 ]# }$ S0 D+ _
- @for(car(I):/ |( ^) f/ P3 a- b0 c# G
- a(1,1,I)=1;a(10,10,I)=1);( d% B: P\" {0 `8 g3 a* C* J) ]) O7 K
- / x' k7 E7 R, k* O
- !每个任务只能有一个;: \& }* J0 w6 K3 n\" h\" d
- @sum(car(I):1 d, Y' t8 w2 Z5 r, Q- q
- @sum(place(K):9 S: P! n6 A7 i& `# g+ o
- @sum(place(J): a(J,K,I))))=1;
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3 T2 ]' G k, T5 c\" \\" H6 K- !每个车的任务最多有四个;! B, Q ^) }% R
- @for(car(I): g! ?, g' S! }/ N+ Y
- @sum(plan(J,K,I):a(J,k,I))<=6);
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& P3 {7 V+ [# m3 o- !前一辆车任务大于等于后一辆车;
5 ^% c% V7 _7 d) |( X% z. U: \ - @for(car(I)|I#lt#1:5 p& [. q, {$ O2 L& l; G1 z
- @sum(plan:a(J,K,I))>=@sum(plan:a(J,K,I+1) );
+ a, B! p) O- i6 ~4 _; x2 F
% @2 N( S+ x% @/ H# v; b7 W- !求which 例子 若a(1,:)=[1 0 0 1 0 1 0 0 0 1];. A5 L- R( E. F3 _/ K
- ! 则 which(1,:)=[1 1 1 4 4 6 6 6 6 10] ;
# y S, ~% n* M# x5 P% i1 L- b - @for(car(I):
9 q! A* O' ~2 l0 F - @for(place(kk)|@sum(place(jj):a(kk,jj,I)) #eq#1:
/ B8 o, p3 k! D# Z- K% U - @for(place(jj)|a(kk,jj,I) #eq#1:
' o; F. A/ s+ @ - which(I,kk)=jj ););6 z8 @! e- ?; q% ]7 @. @
- @for(place(kk)|@sum(place(kk):a(kk,jj,I)) #ne#1:
7 A4 f- r9 j: R - which(I,kk)=which(I,kk-1));$ k% }9 }( o1 [! ]( \- m
- - k- l' ?' t0 T/ L6 A5 p6 q; N- B
- !时间限制;: k1 ~# @ K0 \) F3 M$ ]
- @for(car(jjj):- t* i: p* G* z9 k$ M, M
- time(jjj)>=-10;time(jjj)<=7);
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- @for(jiu(jjj):, S\" Q1 w\" J4 n: H
- ct(I,jjj)=@if(which(I,jjj)#ne#which(I,jjj+1),dt(which(I,jjj),which(I,jjj+1))+timexie(which(I,jjj)),0));
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- @for(jiu(jjj):
& F0 V/ ~+ L% V% h/ X - time(I)+ct(I,jjj)>=time1(jjj+1);time(I)+ct(I,jjj)<=time2(jjj+1));
# M& o+ { f# A7 V; q% b+ N/ y - $ ^1 n: ~& }. X, B5 O0 U& \# _( n
- !求每辆车行驶的距离;. Z7 t+ K! b- @\" } Q8 ~$ ~0 d
- @for(jiu(jjj):0 w* s) p9 S2 `$ H4 _% f$ i4 y. A7 q
- lucheng(I,jjj)=@if(which(I,jjj)#ne#which(I,jjj+1),dd(which(I,jjj),which(I,jjj+1)),0) );
# t7 w* X% [+ b- f9 X - );););9 L5 H7 h* a: k; n( [+ L# ~
- end Y) B) a1 _# G4 a; B# h
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