以下是引用hubulwm在2008-5-24 14:23:22的发言:
Local optimal solution found. Objective value: 3029600. Extended solver steps: 0 Total solver iterations: 4 Model Title: Location Problem
Variable Value Reduced Cost Y( 1) 1.000000 -2530500. Y( 2) 1.000000 -499100.0 Y( 3) 0.000000 0.000000 Y( 4) 0.000000 0.000000 A( 1) 27.30000 0.000000 A( 2) 38.20000 0.000000 A( 3) 43.70000 0.000000 A( 4) 35.20000 0.000000 X( 1) 72000.00 0.000000 X( 2) 10000.00 0.000000 X( 3) 0.000000 0.000000 X( 4) 0.000000 0.000000 B( 1) 25000.00 0.000000 B( 2) 12000.00 0.000000 B( 3) 6000.000 0.000000 B( 4) 21000.00 0.000000 B( 5) 8000.000 0.000000 B( 6) 7000.000 0.000000 B( 7) 3000.000 0.000000 W( 1) 28.00000 0.000000 W( 2) 28.00000 0.000000 W( 3) 30.00000 0.000000 W( 4) 28.00000 0.000000 W( 5) 30.00000 0.000000 W( 6) 32.00000 0.000000 W( 7) 32.00000 0.000000 C( 1, 1) 4.500000 0.000000 C( 1, 2) 7.500000 0.000000 C( 1, 3) 10.00000 0.000000 C( 1, 4) 8.000000 0.000000 C( 1, 5) 16.80000 0.000000 C( 1, 6) 28.70000 0.000000 C( 1, 7) 39.60000 0.000000 C( 2, 1) 23.60000 0.000000 C( 2, 2) 21.00000 0.000000 C( 2, 3) 23.80000 0.000000 C( 2, 4) 28.50000 0.000000 C( 2, 5) 18.30000 0.000000 C( 2, 6) 9.700000 0.000000 C( 2, 7) 16.40000 0.000000 C( 3, 1) 29.30000 0.000000 C( 3, 2) 27.00000 0.000000 C( 3, 3) 41.00000 0.000000 C( 3, 4) 32.70000 0.000000 C( 3, 5) 13.80000 0.000000 C( 3, 6) 8.000000 0.000000 C( 3, 7) 11.00000 0.000000 C( 4, 1) 15.80000 0.000000 C( 4, 2) 19.20000 0.000000 C( 4, 3) 19.00000 0.000000 C( 4, 4) 19.30000 0.000000 C( 4, 5) 7.800000 0.000000 C( 4, 6) 11.00000 0.000000 C( 4, 7) 17.00000 0.000000 Z( 1, 1) 1.000000 0.000000 Z( 1, 2) 1.000000 0.000000 Z( 1, 3) 1.000000 0.000000 Z( 1, 4) 1.000000 0.000000 Z( 1, 5) 1.000000 0.000000 Z( 1, 6) 0.000000 56700.00 Z( 1, 7) 0.000000 36900.00 Z( 2, 1) 0.000000 750000.0 Z( 2, 2) 0.000000 292800.0 Z( 2, 3) 0.000000 148200.0 Z( 2, 4) 0.000000 659400.0 Z( 2, 5) 0.000000 99200.00 Z( 2, 6) 1.000000 0.000000 Z( 2, 7) 1.000000 0.000000 Z( 3, 1) 0.000000 1825000. Z( 3, 2) 0.000000 848400.0 Z( 3, 3) 0.000000 508200.0 Z( 3, 4) 0.000000 1604400. Z( 3, 5) 0.000000 460000.0 Z( 3, 6) 0.000000 361900.0 Z( 3, 7) 0.000000 164100.0 Z( 4, 1) 0.000000 1275000. Z( 4, 2) 0.000000 652800.0 Z( 4, 3) 0.000000 325200.0 Z( 4, 4) 0.000000 1144500. Z( 4, 5) 0.000000 344000.0 Z( 4, 6) 0.000000 323400.0 Z( 4, 7) 0.000000 156600.0 T( 1, 1) 23.00000 0.000000 T( 1, 2) 24.00000 0.000000 T( 1, 3) 24.50000 0.000000 T( 1, 4) 24.00000 0.000000 T( 1, 5) 26.50000 0.000000 T( 1, 6) 30.00000 0.000000 T( 1, 7) 33.00000 0.000000 T( 2, 1) 32.00000 0.000000 T( 2, 2) 31.00000 0.000000 T( 2, 3) 31.50000 0.000000 T( 2, 4) 33.00000 0.000000 T( 2, 5) 30.50000 0.000000 T( 2, 6) 28.50000 0.000000 T( 2, 7) 29.50000 0.000000 T( 3, 1) 34.50000 0.000000 T( 3, 2) 33.50000 0.000000 T( 3, 3) 37.00000 0.000000 T( 3, 4) 35.50000 0.000000 T( 3, 5) 30.50000 0.000000 T( 3, 6) 29.00000 0.000000 T( 3, 7) 30.00000 0.000000 T( 4, 1) 29.00000 0.000000 T( 4, 2) 30.00000 0.000000 T( 4, 3) 30.00000 0.000000 T( 4, 4) 30.00000 0.000000 T( 4, 5) 27.00000 0.000000 T( 4, 6) 27.50000 0.000000 T( 4, 7) 29.50000 0.000000 Row Slack or Surplus Dual Price OBJ 3029600. -1.000000 2 5.000000 0.000000 3 4.000000 0.000000 4 5.500000 0.000000 5 4.000000 0.000000 6 3.500000 0.000000 7 32.00000 0.000000 8 32.00000 0.000000 9 28.00000 0.000000 10 28.00000 0.000000 11 30.00000 0.000000 12 28.00000 0.000000 13 30.00000 0.000000 14 3.500000 0.000000 15 2.500000 0.000000 16 28.00000 0.000000 17 28.00000 0.000000 18 30.00000 0.000000 19 28.00000 0.000000 20 30.00000 0.000000 21 32.00000 0.000000 22 32.00000 0.000000 23 28.00000 0.000000 24 28.00000 0.000000 25 30.00000 0.000000 26 28.00000 0.000000 27 30.00000 0.000000 28 32.00000 0.000000 29 32.00000 0.000000 30 0.000000 -795000.0 31 0.000000 -417600.0 32 0.000000 -223800.0 33 0.000000 -741300.0 34 0.000000 -352800.0 35 0.000000 -335300.0 36 0.000000 -163800.0 37 0.000000 0.000000 38 0.000000 27.30000 39 0.000000 38.20000 40 0.000000 43.70000 41 0.000000 35.20000 请问你是用什么版本的lingo运行的,能告诉我么?谢谢了 我需要下能运行的LINGO进行截图,论文使用~拜托了
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