求帮助，关于S1的积分，为什么我的结果带int啊，这是怎么回事。正确的应该怎么办！！

dyd

syms g v aA bA cA zA u  t1 t2;
int(g);
' q* v/ b) e4 r' p8 G7 B; E+ zint(v);
h=0.856;
% |+ O7 ^$ `, P  P5 ?4 eaA=(1+tan(g)*tan(g));
+ ~# C+ O! T3 FbA=-(2*1.625+2*tan(g)*(h+30*tan(g))-30*tan(g));
9 P& b2 |7 O# u4 h7 Q: ucA=(h+30*tan(g)-15)*(h+30*tan(g)-15);
) E! y! p$ w% b6 tzA=(-bA-sqrt(bA*bA-4*aA*cA))/(2*aA);
# f9 |# n: _2 Cya=h+30*tan(g)-tan(g)*zA;
4 y( _  C  m0 F( Y- h( P6 ?s1=(1.625*1.625-(z-1.625)*(z-1.625))*cos(v)*sqrt(tan(v)*tan(v)+1)*(sin(2*((asin(((h+30*tan(g)-z*tan(g))-15)/(sqrt(1.625*1.625-(z-1.625)*(z-1.625))*sqrt(tan(v)*tan(v)+1))))))/2-sin(2*((asin(-1/(cos(v)*sqrt(tan(v)*tan(v)+1))))))/2+((asin(((h+30*tan(g)-z*tan(g))-15)/(sqrt(1.625*1.625-(z-1.625)*(z-1.625))*sqrt(tan(v)*tan(v)+1)))))+((asin(-1/(cos(v)*sqrt(tan(v)*tan(v)+1))))));
p=1.625-sqrt(1.625^2-((15-ya)/sqrt(tan(v)*tan(v)+1)));
' X2 e3 A/ p& Y- z. S( g& X1 f/ |% {H=int(s1,z,p,10);

厚积薄发

放个截图看看

①不小xin--!

啊啊啊啊啊啊是的的的的飞飞飞

dyd

厚积薄发 发表于 2012-5-9 16:25
9 e/ `4 d! R' o! c! ]) I, D2 I/ q+ e放个截图看看

9 b; }# h0 W6 i* e# H; r
好了···我想得到的是带g v h 但是对s1积分却积分不出来，即使积出来也带int 谢谢了

ealx0yJu

呵呵,打酱油的.