求帮助，关于S1的积分，为什么我的结果带int啊，这是怎么回事。正确的应该怎么办！！

dyd

syms g v aA bA cA zA u  t1 t2;
int(g);
" z& o& T5 c$ `1 B4 r7 A# Iint(v);
h=0.856;
aA=(1+tan(g)*tan(g));
bA=-(2*1.625+2*tan(g)*(h+30*tan(g))-30*tan(g));
; E; d; h8 f$ \9 b2 l& ecA=(h+30*tan(g)-15)*(h+30*tan(g)-15);
3 }+ [# A% x4 }6 u( FzA=(-bA-sqrt(bA*bA-4*aA*cA))/(2*aA);
0 E- i" q' M; i+ O8 O7 q  Qya=h+30*tan(g)-tan(g)*zA;
& J6 r" A0 N0 w+ }s1=(1.625*1.625-(z-1.625)*(z-1.625))*cos(v)*sqrt(tan(v)*tan(v)+1)*(sin(2*((asin(((h+30*tan(g)-z*tan(g))-15)/(sqrt(1.625*1.625-(z-1.625)*(z-1.625))*sqrt(tan(v)*tan(v)+1))))))/2-sin(2*((asin(-1/(cos(v)*sqrt(tan(v)*tan(v)+1))))))/2+((asin(((h+30*tan(g)-z*tan(g))-15)/(sqrt(1.625*1.625-(z-1.625)*(z-1.625))*sqrt(tan(v)*tan(v)+1)))))+((asin(-1/(cos(v)*sqrt(tan(v)*tan(v)+1))))));
- _8 V$ N0 l) n9 z( Q; K/ T" v$ {p=1.625-sqrt(1.625^2-((15-ya)/sqrt(tan(v)*tan(v)+1)));
' q8 ?  a; J7 V: f, k+ W% eH=int(s1,z,p,10);

厚积薄发

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①不小xin--!

啊啊啊啊啊啊是的的的的飞飞飞

dyd

厚积薄发 发表于 2012-5-9 16:25
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6 Z% \; P6 ]4 o
好了···我想得到的是带g v h 但是对s1积分却积分不出来，即使积出来也带int 谢谢了

ealx0yJu

呵呵,打酱油的.