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升级   79.5% TA的每日心情 | 奋斗 2016-1-29 12:24 |
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签到天数: 81 天 [LV.6]常住居民II
- 自我介绍
- 数学建模准备中...
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gancm 发表于 2014-7-19 12:30 ![]()
* a) q) F0 [% E+ M% J# V& I' ]看了图我感觉是网络输出后面那几个值太大了,前面基本都是一条水平线了,具体哪里还看不出问题。你把修改的 ...
0 b" h# k n! {因为版本更新,Matlab中的Newff命令用法有所改变,原命令为:
) f# P: Y% j7 |$ inet=newff(dx,[3,7,2]{'tansig','tansig','purelin'},'traingdx');
. O6 |8 }: }* I, \' Y8 a( v# e我修改为:
5 J% D4 V; K& J0 z! E/ a7 enet=newff(p,t,[3,7,2],{'tansig','tansig','purelin'},'traingdx');5 C6 }" q# o" I, z1 w1 u
然后有些命令被其他命令替代了,其中有premnmx,postmnmx,tramnmx命令好像被替换了,使用了一个强大的命令mapminmax。原命令为:1 ^1 e% ~$ n3 O
[pn,minp,maxp,tn,mint,maxt]=premnmx(p,t);
" B4 I6 C$ x9 R/ y* i' J8 z" E. Ka=postmnmx(an,mint,maxt); _" b# `6 _8 Y$ a4 l# B
pnewn=tramnmx(pnew,minp,maxp);$ \9 s+ g5 X0 `5 d O" h- n! K
anew=postmnmx(anewn,mint,maxt)
4 V) L" n6 w5 U3 M& l我修改为:
8 C7 m$ v$ a m. T: g[pn,ps1]=mapminmax(p);[tn,ps2]=mapminmax(t);+ H2 d1 G( n# r/ d
a=mapminmax('reverse',an,ps2);
# C% O6 O, W; F4 Lpnewn=mapminmax('apply',pnew,ps1);
1 l4 a% u8 D7 G: `' `% X9 X3 nanew=mapminmax('reverse',anewn,ps2)
& j: V0 C0 Q- _; ^" J, }/ S0 S6 S
6 r& n9 `1 T, p- Y3 Y原程序为:5 ]/ R; [7 n. B. U0 s$ m
%原始数据输入% K/ k7 V) v( O: Z+ s8 A
clc
3 n7 O3 v5 ?: [5 s$ x! [, Asqrs=[20.55,22.44,25.73,27.13,29.45,30.1,30.96,34.06,36.42,38.09,39.13,39.99,...* @+ M! Q9 g( O
41.93,44.59,47.30,52.89,55.73,56.76,59.17,60.63];
/ v3 N8 {- B8 D& `1 f- ~sqjdcs=[0.6,0.75,0.85,0.90,1.05,1.35,1.45,1.60,1.70,1.85,2.15,2.20,2.25,2.35,...
]7 Q5 e' g8 C* X; { 2.5,2.6,2.7,2.85,2.95,3.10];
1 E% C. I! G0 p* Y, c9 vsqglmj=[0.09,0.11,0.11,0.14,0.20,0.23,0.23,0.32,0.32,0.34,0.36,0.36,0.38,0.49,...8 p$ L/ ^+ \ K& w5 M5 h4 z
0.56,0.59,0.59,0.67,0.69,0.79];* J5 K$ K" Y8 S- N) F
glkyl=[5126,6217,7730,9145,10460,11387,12353,15750,18304,19836,21024,19490,20433,...
( \/ z5 q9 [. n. e A 22598,25107,33442,36836,40548,42927,43462];
# u- C: ]% R% m' `glhyl=[1237,1379,1385,1399,1663,1714,1834,4322,8132,8936,11099,11203,10524,11115,...
8 U: f1 v1 b1 h, ^ 13320,16762,18673,20724,20803,21804];6 e3 x8 [# \1 |
p=[sqrs;sqjdcs;sqglmj];2 ^6 r0 w. k" L5 E+ r8 ~* F
t=[glkyl;glhyl]; t# z$ e- C6 n. I2 [2 C( X
# d* [/ V+ l9 E; P3 m: n
%数据归一化
! Z1 i W! R9 G/ p' P* F; `, z3 Q[pn,minp,maxp,tn,mint,maxt]=premnmx(p,t);
: A7 Q$ S f9 h9 Odx=[-1,1;-1,1;-1,1];. O% p$ ^: t7 R2 m. b7 m
' h/ p @! A$ X4 z%BP网络训练. p+ q" N K7 W
net=newff(dx,[3,7,2],{'tansig','tansig','purelin'},'traingdx');
- u, q3 U! N- A; y$ Pnet.trainParam.show=1000;5 {; k3 V$ x; A1 e0 P# y" I
net.trainParam.Lr=0.05;& U4 b# U) R* @' k; J! I
net.trainParam.epochs=50000;+ q3 i0 g/ n8 M& p
net.trainParam.goal=0.65*10^(-3);$ Y' x2 x! O6 c/ E3 T& R6 d! B
net=train(net,pn,tn);. e6 e% P& y: K! u
8 k) Y/ n- H9 a. ~+ D: e$ a
%利用原数据对BP网络仿真- n) H. J& k+ H5 j6 W
an=sim(net,pn);
8 }4 S3 ]7 c6 T1 p# x9 k4 ha=postmnmx(an,mint,maxt);
5 A; c' m& S1 g3 j, B7 B% c+ O( n8 ^$ q& \- U5 {
%仿真结果与原数据对比测试9 m# m6 {( F1 m1 U8 r# Y8 \6 R y
x=1990:2009;
& m1 ?, d; s9 Y% ^8 knewk=a(1, ;" e$ v# P/ q. L
newh=a(2, ;
7 [' G' o7 r8 dfigure(2);
7 p+ V7 B/ J, t& U; J Zsubplot(2,1,1);plot(x,newk,'r-o',x,glkyl,'b--+');2 B1 ]- t% B6 o1 n9 i6 H
legend('网络输出客运量','实际客运量');3 O. O- c( W% U
xlabel('年份');ylabel('货运量、万人');
4 F* y& o) W0 |! w% i+ z4 u' btitle('运用工具箱客运量学习和测试对比图');) R" B$ F2 ]9 |; t) c
subplot(2,1,2);plot(x,newh,'r-o',x,glhyl,'b--+'); z; r# N0 S+ `! m( [# x
legend('网络输出货运量','实际货运量');
; s# O) E3 q2 Y6 O! v& Cxlabel('年份');ylabel('货运量、万吨');
, b8 M4 i; u- }1 I/ Y6 R, b6 r6 Stitle('运用工具箱货运量学习和测试对比图');( h) @1 A. s1 B4 R, r1 `
! d7 d2 O- ~; L; c$ y
%新数据仿真
) M0 M+ C" N' i+ Gpnew=[73.39,75.55
4 r. V; U% N- j 3.9635,4.0975
/ y m- l4 _) p; N 0.9880,1.0268];, K* \" R# V6 y" n
pnewn=tramnmx(pnew,minp,maxp);
. j3 a- E) h* p. ~6 danewn=sim(net,pnewn);
. N+ e. U0 w9 x6 k7 ^anew=postmnmx(anewn,mint,maxt)
3 B, c" @/ q+ n6 c) U# Y- w5 Y$ O" o6 g! I
修改后程序为:
8 A# `* r0 t' U4 j4 I$ S+ X0 c" O%原始数据输入
0 s. a, P' r T" N- |' yclc- z* [% Z! V% Z, N
sqrs=[20.55,22.44,25.73,27.13,29.45,30.1,30.96,34.06,36.42,38.09,39.13,39.99,...
2 V0 G& s6 E) ^1 L5 F 41.93,44.59,47.30,52.89,55.73,56.76,59.17,60.63];
( e+ n9 P4 p H. ^sqjdcs=[0.6,0.75,0.85,0.90,1.05,1.35,1.45,1.60,1.70,1.85,2.15,2.20,2.25,2.35,...
% E0 y; j4 p3 ?5 ^6 K 2.5,2.6,2.7,2.85,2.95,3.10];
# T$ w+ t9 ~3 nsqglmj=[0.09,0.11,0.11,0.14,0.20,0.23,0.23,0.32,0.32,0.34,0.36,0.36,0.38,0.49,...
9 e7 Q1 Z9 p% I0 s* \3 F6 g& [( J 0.56,0.59,0.59,0.67,0.69,0.79]; ?; M3 k6 e: y& j, s% @* V2 n
glkyl=[5126,6217,7730,9145,10460,11387,12353,15750,18304,19836,21024,19490,20433,.../ t3 S9 Z8 U$ c- b1 e3 f
22598,25107,33442,36836,40548,42927,43462];; p. m) B7 F2 R) ]1 ^
glhyl=[1237,1379,1385,1399,1663,1714,1834,4322,8132,8936,11099,11203,10524,11115,...
9 O: P8 i; B+ H 13320,16762,18673,20724,20803,21804];/ L1 M5 A3 C2 [" K9 w$ ^
p=[sqrs;sqjdcs;sqglmj];
6 H/ G- a* S, a- ?, \: ut=[glkyl;glhyl];$ O. p& U) h5 u$ z! f
! a: E' j; Z" k6 j- m
%数据归一化
2 I" [% I6 @: T[pn,ps1]=mapminmax(p);& y9 v0 C; \- g- b) r/ v+ j, S9 [
[tn,ps2]=mapminmax(t);
3 J' j: S4 s T f& c: l$ l0 {' p/ M0 Z, X. v
%BP网络训练
! p% @- x, [3 Y3 ^- qnet=newff(p,t,[3,7,2],{'tansig','tansig','purelin'},'traingdx');) a A( O" r: u% [
net.trainParam.show=1000;+ j! |9 o1 Y: d! Y, \! }& A$ N
net.trainParam.Lr=0.05;
; ^; c+ `- u% W; A$ ^! Xnet.trainParam.epochs=50000;
1 z, R4 o1 ]) S9 q9 k6 [net.trainParam.goal=0.65*10^(-3);& D/ h6 u* i. l# }9 m- m
net=train(net,pn,tn);7 Y# e! D9 [, A9 \/ {3 F, U
" G9 o+ u$ I i! J3 N+ @4 W7 a%利用原数据对BP网络仿真0 Y" o* E: s& K- y* W& B
an=sim(net,pn);" N* L- O# e2 k" n
a=mapminmax('reverse',an,ps2);: P+ @" S/ p9 h" G
( n# t8 b& [ C- a
%仿真结果与原数据对比测试: x! V7 |- T/ z; q3 R: x
x=1990:2009;
. l$ H* J3 r9 Qnewk=a(1, ;- X# d V; {" k- _6 R
newh=a(2, ;
9 p/ [: h1 p9 O7 yfigure(2);; F) b! h. M& ^
subplot(2,1,1);plot(x,newk,'r-o',x,glkyl,'b--+');
9 w1 I: b7 ?1 n Elegend('网络输出客运量','实际客运量');9 B( d4 K, O, y9 w- F) \/ S# ^
xlabel('年份');ylabel('货运量、万人');
" V) D$ p7 [2 i; ytitle('运用工具箱客运量学习和测试对比图');) D( K- s" W$ ~( k( A' ^+ E, O
subplot(2,1,2);plot(x,newh,'r-o',x,glhyl,'b--+');# P+ Q' I ]! J! c
legend('网络输出货运量','实际货运量');
' p: X+ S. D0 b2 |- Yxlabel('年份');ylabel('货运量、万吨');5 G- [3 z0 f3 H2 t% k
title('运用工具箱货运量学习和测试对比图');
; }2 Q& t, I: h! j4 e2 G
6 X3 k5 Q: _" \%新数据仿真
3 m, h6 ~& T- |9 R& a* ~, V* bpnew=[73.39,75.554 M3 E% K5 u; d+ d0 R+ T
3.9635,4.0975
% f, g& x$ r& D1 N5 n$ S. E! e+ ~* g6 P 0.9880,1.0268];9 j2 ^, ]' e7 i+ K* @# N
pnewn=mapminmax('apply',pnew,ps1);
% g% @" R9 d4 {& U! C" |/ L' zanewn=sim(net,pnewn);# K# F- a) P& K+ Z; }) j% `
anew=mapminmax('reverse',anewn,ps2)
6 d, E2 J5 X- Y, |9 h2 v(修改的地方用颜色标记了)
/ l: ]/ A2 ~) N& |麻烦您帮忙指出其中的问题,万分感谢! |
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