谁来帮忙看一下这个题错在哪里？

Winter_moon

Cryptoquote
$ U6 J: Y) H, @2 X" u
3 M! d( E+ B0 Q' ?: |
( Y: F+ M% [9 j7 ?Time Limit: 1000 ms Memory Limit: 65536 kB
Solved: 79 Tried: 281

4 e! M$ N0 y& A/ t" S+ `Description
A cryptoquote is a ** encoded message where one letter is simply replaced by another throughout the message. For example:
( a* u2 ~* w) r9 w$ J# v; O
Encoded: HPC PJVYMIY
Decoded: ACM CONTEST
* x2 V) w4 S& E
- h+ y9 p: @# YIn the example above, H=A, P=C, C=M, J=O, V=N, Y=T, M=E and I=S. For this problem, you will decode messages.
1 j% H* |7 Q1 H* `& d4 h; U4 u
( E% k' ^3 V; J) D7 A* D$ W) A) {
Input
The first line of input contains a single integer N,(1<=N<=1000) which is the number of data sets that follow. Each data set consists of two lines of input. The first line is the encoded message. The second line is a 26 character string of upper case letters giving the character mapping for each letter of the alphabet: the first character gives the mapping for A, the second for B and so on. Only upper case letters will be used. Spaces may appear in the encoded message, and should be preserved in the output string.
! n. G% T6 K3 R/ C" D9 k9 v9 J" [
: {8 n% ~1 s; B/ }
* l* q0 D4 Z" U" Q3 U! ?
! e8 D& W# I* A# h3 ^Output
' V* Y5 V- R6 h! Q; ]- gFor each data set, you should generate one line of output with the following values: The data set number as a decimal integer (start counting at one), a space and the decoded message.
1 {7 M1 G( E0 q7 B4 I- O, H
  r2 u% ]- G- p, X' H1 x' d
Sample Input
2
# B7 C0 S/ a9 ~$ v3 o% ~0 VHPC PJVYMIY
% g1 a1 M1 y' ^; DBLMRGJIASOPZEFDCKWYHUNXQTV
& X0 F4 u4 ]/ D$ y9 F7 QFDY GAI BG UKMY
9 H; g9 I+ ~( O6 Z! n4 yKIMHOTSQYRLCUZPAGWJNBVDXEF


5 X% F( J# S# O1 C
Sample Output
1 ACM CONTEST
2 THE SKY IS BLUE

% D* c. {  i5 K4 l% s
3 A; [6 T& p% U' S% ^+ |) M6 v
我的代码是：
#include<stdio.h>
#include<string.h>
int main()
{
3 F1 K7 w6 E. w2 v, w3 ^' D     int N,i,j,k;
     char c;
     char code[1000];
' @0 F3 N1 V8 ?+ j! ^( u  \% q     char map[27];
5 A5 r' N, A8 K7 f+ g+ N     char trans[1000];
     char wrong[3];
, G  q2 e) y6 N, P     scanf("%d",&N);
     gets(wrong);
4 C! U2 U3 m( A3 q4 t- w; a) G     int h=1;
8 n% x# f# q/ `0 Q" w- h2 _     while(N--)
; L- H$ V3 f; a1 ^( l' \8 N     {
         gets(code);
         gets(map);
         for(i=0;((c=code[i])!='\0');i++)
         {
             if(c==' ')trans[i]=' ';
" _+ ?0 u+ @3 T7 V             else {j=code[i]-'A';
& X, c  P: }  h% v             trans[i]=map[j];}       }
         printf("%d ",h);
         for(i=0;((k=trans[i]<=90)&&(k=trans[i]>=65)||(k=trans[i]==' '));i++)
         printf("%c",trans[i]);
         h++;
         printf("\n");
     }
+ n& {0 x+ y/ S     return 0;
' @! {1 }" F& y7 l6 V* u3 H}


样例过了，但是提交答案的时候还是wrong answer。是哪里有陷阱？
0 {, s6 X% g0 W% _& q; [6 N

zjqylcy

把答案也附上来吗。。。
: L% E' i/ k% O, ]是不是k是int型？

葉_浅浅

.....................

linmatsas

C………………………………

_我还活着

没有看懂.....

huangliao6252

int h=1;这个定义应该在 scanf("%d",&N);前面。