谁来帮忙看一下这个题错在哪里？

Winter_moon

Cryptoquote
0 ]- k6 x) K2 s' g  a6 K! j
3 S% G9 {. W+ ^( G
) g8 f* C( z$ S3 D, i) x3 Z% C3 bTime Limit: 1000 ms Memory Limit: 65536 kB
Solved: 79 Tried: 281
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Description
A cryptoquote is a ** encoded message where one letter is simply replaced by another throughout the message. For example:
/ j3 m5 X) a/ p  }' q
& g# m1 ]1 {' G5 Z# ^: ?- a* BEncoded: HPC PJVYMIY
Decoded: ACM CONTEST
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- J$ l: R: n2 V1 d4 W2 u0 KIn the example above, H=A, P=C, C=M, J=O, V=N, Y=T, M=E and I=S. For this problem, you will decode messages.
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7 s0 K& n. ^" ?+ NInput
$ s  R- V! L3 O, v. ^: K5 gThe first line of input contains a single integer N,(1<=N<=1000) which is the number of data sets that follow. Each data set consists of two lines of input. The first line is the encoded message. The second line is a 26 character string of upper case letters giving the character mapping for each letter of the alphabet: the first character gives the mapping for A, the second for B and so on. Only upper case letters will be used. Spaces may appear in the encoded message, and should be preserved in the output string.



Output
$ m7 g' H, i/ s& ]& ]For each data set, you should generate one line of output with the following values: The data set number as a decimal integer (start counting at one), a space and the decoded message.

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/ {$ F; J$ g  B) T- j! N5 aSample Input
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HPC PJVYMIY
  x: L4 @: g! `# S- @9 vBLMRGJIASOPZEFDCKWYHUNXQTV
( c' i  O- V7 g! Q* }FDY GAI BG UKMY
; y( v4 O& ~! S% h2 P, q0 jKIMHOTSQYRLCUZPAGWJNBVDXEF
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8 A  t: a. D1 n% L5 E4 g8 x; R7 VSample Output
1 ACM CONTEST
2 THE SKY IS BLUE
! A3 X2 J" B9 R" W
* h+ h- \( O1 B* y4 m, S4 d
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0 _# h  R. C  r) Q我的代码是：
) p- v# U4 w* }. @#include<stdio.h>
0 \. V7 ^+ M6 @2 U6 w; h#include<string.h>
int main()
) k- O& \5 h) ]. \& R; ]{
     int N,i,j,k;
     char c;
6 ?+ ]# B6 g( [0 x: R7 H- R0 t     char code[1000];
- K# d* |& p! d. y     char map[27];
     char trans[1000];
     char wrong[3];
3 p# m, E4 U" _$ `/ Z     scanf("%d",&N);
" B2 p9 A/ J! L# [- j0 T& D3 ]     gets(wrong);
     int h=1;
; M7 N( l6 v. s1 b3 K     while(N--)
     {
* o+ {- f+ d: Z% o         gets(code);
6 S! w6 y5 f9 q, y0 J         gets(map);
+ }1 M/ ^# C" [* U0 T( j         for(i=0;((c=code[i])!='\0');i++)
; F9 A0 P- h- V' k8 _, h) O         {
9 k* D; ^' N, a  H             if(c==' ')trans[i]=' ';
5 Y/ b* H) ~" z% _             else {j=code[i]-'A';
             trans[i]=map[j];}       }
         printf("%d ",h);
5 |! z0 G+ z. D5 ~! ]. t         for(i=0;((k=trans[i]<=90)&&(k=trans[i]>=65)||(k=trans[i]==' '));i++)
         printf("%c",trans[i]);
  a+ ~4 @! Y/ I5 L         h++;
5 m$ {% y2 {$ b# c         printf("\n");
/ w# D1 S" v7 W) }3 g     }
# z! ?4 C. J. f4 N* Y, F. ~     return 0;
}
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样例过了，但是提交答案的时候还是wrong answer。是哪里有陷阱？

zjqylcy

把答案也附上来吗。。。
是不是k是int型？

葉_浅浅

.....................

linmatsas

C………………………………

_我还活着

没有看懂.....

huangliao6252

int h=1;这个定义应该在 scanf("%d",&N);前面。