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升级   79.5% TA的每日心情 | 奋斗 2016-1-29 12:24 |
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签到天数: 81 天 [LV.6]常住居民II
- 自我介绍
- 数学建模准备中...
|
gancm 发表于 2014-7-19 12:30 ![]()
4 H# I/ P+ ^/ b, x! v- J8 I0 {看了图我感觉是网络输出后面那几个值太大了,前面基本都是一条水平线了,具体哪里还看不出问题。你把修改的 ...
9 y, q$ W! j ^4 r2 h. `因为版本更新,Matlab中的Newff命令用法有所改变,原命令为:
; Z; {. J/ T o' _# `& G3 Rnet=newff(dx,[3,7,2]{'tansig','tansig','purelin'},'traingdx');
" |; K/ F- D1 V6 V我修改为:
; _* U( K8 X8 \( P/ f. Ynet=newff(p,t,[3,7,2],{'tansig','tansig','purelin'},'traingdx');4 r3 G3 E+ Y) M7 g
然后有些命令被其他命令替代了,其中有premnmx,postmnmx,tramnmx命令好像被替换了,使用了一个强大的命令mapminmax。原命令为:
/ g) G1 N" I3 l/ p[pn,minp,maxp,tn,mint,maxt]=premnmx(p,t);
+ s$ e! w1 x `$ wa=postmnmx(an,mint,maxt);
) R, y. k" {$ `pnewn=tramnmx(pnew,minp,maxp);3 T5 x5 u; |; Q8 V1 M7 ~+ j! a8 X
anew=postmnmx(anewn,mint,maxt)
7 \5 @5 o6 V9 i7 K: W9 n我修改为:7 J$ U* h$ F% l8 ]8 Z5 _
[pn,ps1]=mapminmax(p);[tn,ps2]=mapminmax(t);% w. {" G3 {6 H
a=mapminmax('reverse',an,ps2);: b7 B& W" Z* n8 z9 C _# k1 d2 b+ O
pnewn=mapminmax('apply',pnew,ps1);
^4 h/ p, j6 @6 Yanew=mapminmax('reverse',anewn,ps2)4 _# |; \3 S# w$ U( b H; d* N- t
: F0 {6 D7 Z+ z, E: \! l原程序为:7 U+ _8 J# ]7 a+ w5 o) I- Z
%原始数据输入
l1 x7 G* k0 S: ?7 {clc
: i# g \) A8 }. V, O1 usqrs=[20.55,22.44,25.73,27.13,29.45,30.1,30.96,34.06,36.42,38.09,39.13,39.99,...6 T* z- G$ ~, B1 k3 g. s4 Y
41.93,44.59,47.30,52.89,55.73,56.76,59.17,60.63];) x9 m" D$ G b, J- X& ?
sqjdcs=[0.6,0.75,0.85,0.90,1.05,1.35,1.45,1.60,1.70,1.85,2.15,2.20,2.25,2.35,...3 D2 b& h! D( u% n* V
2.5,2.6,2.7,2.85,2.95,3.10];# ~6 l' U, ^5 d3 E
sqglmj=[0.09,0.11,0.11,0.14,0.20,0.23,0.23,0.32,0.32,0.34,0.36,0.36,0.38,0.49,...
% ^0 K" ? |9 a! B. M" i* ^ 0.56,0.59,0.59,0.67,0.69,0.79];
8 ]. N& s' e% K' y2 ]glkyl=[5126,6217,7730,9145,10460,11387,12353,15750,18304,19836,21024,19490,20433,...
! G9 o9 }+ _" R7 P, g- L 22598,25107,33442,36836,40548,42927,43462];
. ^7 C: }: C+ [7 o% E; E2 q. ]glhyl=[1237,1379,1385,1399,1663,1714,1834,4322,8132,8936,11099,11203,10524,11115,...& y4 Y5 U& K7 R7 O7 |. M& [* f
13320,16762,18673,20724,20803,21804];
9 b, T$ t1 p8 ?5 E( k3 @/ R) h* hp=[sqrs;sqjdcs;sqglmj];9 [! u8 Z0 d" }5 R1 }( C* C
t=[glkyl;glhyl];
$ B% g! F, B3 \7 J3 X+ L% f
5 ^& s+ @$ e( j/ ]( A' e%数据归一化3 g& W) {' L( h3 J% N9 _
[pn,minp,maxp,tn,mint,maxt]=premnmx(p,t);
/ z; N! I1 P# t7 Qdx=[-1,1;-1,1;-1,1];) i; F7 O; d! c/ d' |+ r! {) q
2 h/ @. a0 ?, V' g: ?$ Y
%BP网络训练
. e# k0 [, g2 b1 `net=newff(dx,[3,7,2],{'tansig','tansig','purelin'},'traingdx');
/ U8 e0 \7 b# B, D/ Xnet.trainParam.show=1000;
% L' S% ]2 V7 [" _) @+ ?net.trainParam.Lr=0.05;
4 u9 g7 W% P# n) \* w$ y/ H5 unet.trainParam.epochs=50000;1 m' W8 N. B/ ?) X
net.trainParam.goal=0.65*10^(-3);
3 S1 o. E; t0 r/ L# ?5 _net=train(net,pn,tn);
~1 L- i( Q6 p# K/ g% K" G6 K: O
/ C, G) [7 q8 s& o%利用原数据对BP网络仿真
/ s5 }' B! B2 z4 Pan=sim(net,pn);
6 Y: [6 n( ~# {5 ~a=postmnmx(an,mint,maxt);
6 f" V$ E+ b% I1 \4 w- y; | Q( y! r: E) B! w) J" y# Q4 Z$ v i6 n
%仿真结果与原数据对比测试# P" `: ]$ z" Q- X8 f
x=1990:2009;
7 C) S2 t5 q4 L- d+ qnewk=a(1, ;7 _4 n) J( R* I
newh=a(2, ;% h! A x: g% N: n1 z
figure(2);4 \+ T# A$ Z" L, t5 n8 n7 i
subplot(2,1,1);plot(x,newk,'r-o',x,glkyl,'b--+');
6 {) S* A7 V# ~- E: M) nlegend('网络输出客运量','实际客运量'); V$ o6 a. j0 G
xlabel('年份');ylabel('货运量、万人');1 _% A% B7 v: E) I5 W r1 B
title('运用工具箱客运量学习和测试对比图');3 q( ?6 v0 H. @/ V& o9 q! Q
subplot(2,1,2);plot(x,newh,'r-o',x,glhyl,'b--+');
, ?1 \! d" c4 d' R( u/ Olegend('网络输出货运量','实际货运量');
3 C% v5 |- C# o1 xxlabel('年份');ylabel('货运量、万吨');
. w4 G* u. E: stitle('运用工具箱货运量学习和测试对比图');: F5 y7 B- k! ^" r! v, w
+ i" b. F9 f, [' f- p6 j%新数据仿真# b' n7 u- T# R3 z9 k5 Y
pnew=[73.39,75.55
$ `. l) `6 J4 o% V 3.9635,4.0975
+ u( X. H4 f1 |# F% A 0.9880,1.0268];6 ?; J6 \& L: p) i. p
pnewn=tramnmx(pnew,minp,maxp);
1 s7 q- K4 t' Y2 uanewn=sim(net,pnewn);
9 _: k+ B1 R# a4 T. ^anew=postmnmx(anewn,mint,maxt)
' {9 d" `6 ?8 ^/ f A, P
7 g9 F) q, n/ x+ p5 w修改后程序为:
i7 b& x0 B2 h# h2 u%原始数据输入. s$ v' u" P, n8 E9 C
clc# z _2 k4 D) R9 |9 T! I2 ]( J
sqrs=[20.55,22.44,25.73,27.13,29.45,30.1,30.96,34.06,36.42,38.09,39.13,39.99,...
& U2 F8 g+ Q# I( K4 K8 U 41.93,44.59,47.30,52.89,55.73,56.76,59.17,60.63];
% s% e, p2 ]+ ]# I Tsqjdcs=[0.6,0.75,0.85,0.90,1.05,1.35,1.45,1.60,1.70,1.85,2.15,2.20,2.25,2.35,...
# T- |9 {9 R/ Z 2.5,2.6,2.7,2.85,2.95,3.10];' M1 {% l6 H3 [/ t
sqglmj=[0.09,0.11,0.11,0.14,0.20,0.23,0.23,0.32,0.32,0.34,0.36,0.36,0.38,0.49,..." p# r5 \; W* \- R' ~
0.56,0.59,0.59,0.67,0.69,0.79];
# ~; l/ M. V! C& Q! ?glkyl=[5126,6217,7730,9145,10460,11387,12353,15750,18304,19836,21024,19490,20433,...7 a3 x0 Q' o; u, t, j: ]8 Q
22598,25107,33442,36836,40548,42927,43462];: P: t! U7 u# {) I
glhyl=[1237,1379,1385,1399,1663,1714,1834,4322,8132,8936,11099,11203,10524,11115,...
; H2 |7 b6 `# `3 s# ~! N: \& K5 w 13320,16762,18673,20724,20803,21804];1 c1 [/ t4 M6 v4 p+ N1 G* }
p=[sqrs;sqjdcs;sqglmj];
& f: ?. F0 E+ G/ O( ~% Kt=[glkyl;glhyl];
. ^- G. g) N* Y& Y. C5 ~& S" |! o7 c- T' V
%数据归一化/ `# z! S0 |) ^ Z2 T! g& ^. D
[pn,ps1]=mapminmax(p);
4 b! k' X, t- d6 }[tn,ps2]=mapminmax(t);7 T( A& Q+ i8 W
\6 Z% k6 J5 N# `' S, f, ^%BP网络训练
! @( q9 c2 t5 f) D4 M2 c) @net=newff(p,t,[3,7,2],{'tansig','tansig','purelin'},'traingdx');
: ~. v2 g O/ K5 h" Bnet.trainParam.show=1000;
# F' Z8 v9 V9 q/ j( Pnet.trainParam.Lr=0.05;
$ R+ P. c7 N! ~. U5 X! i& T ?net.trainParam.epochs=50000;
! v' @( Y! ?3 N" r; Dnet.trainParam.goal=0.65*10^(-3);
+ W) N" t& g; r. t) s( |" ]net=train(net,pn,tn);# Q) O$ u1 `6 Y( n) R" v
3 G8 | q L/ c3 k0 G1 }5 B
%利用原数据对BP网络仿真; I/ O' {, Z$ _3 S+ \2 X7 x0 X9 B
an=sim(net,pn);' c" Q5 G' k& O6 U( i& j6 Y' }
a=mapminmax('reverse',an,ps2);! I! E* R' t1 t2 Y/ c+ D2 \- e: S
9 L5 h9 b& C7 |; O
%仿真结果与原数据对比测试
- e+ {# e$ G. X7 ]( zx=1990:2009;
: z, q; j B" |& P, ], y' cnewk=a(1, ;
7 x/ ~) V) O3 i1 o8 I+ a' vnewh=a(2, ;" ]! X' y8 C3 X7 F2 A
figure(2);
! G% H! E$ Z* c4 y) ^2 [subplot(2,1,1);plot(x,newk,'r-o',x,glkyl,'b--+');) S2 m6 x3 Y* U# I7 `
legend('网络输出客运量','实际客运量');- ^1 [! R+ F& k9 X
xlabel('年份');ylabel('货运量、万人');7 f' N& s) n1 v) @% H
title('运用工具箱客运量学习和测试对比图');
$ p' e l; G! k& Ssubplot(2,1,2);plot(x,newh,'r-o',x,glhyl,'b--+');! |% \5 r- a K; a
legend('网络输出货运量','实际货运量');- I# d/ y* B9 T, s) D
xlabel('年份');ylabel('货运量、万吨');
+ C1 R5 S9 u7 ztitle('运用工具箱货运量学习和测试对比图');" S9 S9 _) z7 P/ t* P& M) K8 N; b
; O2 v+ H, i: i$ |. }%新数据仿真/ E N( a. L' S5 c
pnew=[73.39,75.55
3 {- a4 j: t1 v8 V 3.9635,4.0975% F" @1 }2 _7 ?5 C
0.9880,1.0268];) T( U1 w1 l# n- K
pnewn=mapminmax('apply',pnew,ps1);
2 S( S: ^* `8 T8 }$ O' q& H! \anewn=sim(net,pnewn);" I6 W+ k8 W* u3 x% L( S0 R
anew=mapminmax('reverse',anewn,ps2)
" G' j$ f" i, u(修改的地方用颜色标记了)
, m& a* O+ |' u3 i& r5 E6 `8 E5 X麻烦您帮忙指出其中的问题,万分感谢! |
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