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TA的每日心情 | 开心 2021-8-11 17:59 |
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签到天数: 17 天 [LV.4]偶尔看看III 网络挑战赛参赛者 网络挑战赛参赛者 - 自我介绍
- 本人女,毕业于内蒙古科技大学,担任文职专业,毕业专业英语。
 群组: 2018美赛大象算法课程 群组: 2018美赛护航培训课程 群组: 2019年 数学中国站长建 群组: 2019年数据分析师课程 群组: 2018年大象老师国赛优 |
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最大流: ![]() 注意Matlab 中的最大流问题是必须是单源和单汇问题,因此这里需要构建虚拟的源点S和汇点G。2 o; [5 Q* a' g+ }4 \& Z+ \
clc,clear$ H0 p, G7 d. c3 K1 H
a = zeros(9,9);5 o7 m5 T# {9 z6 l
a(1,[2:4]) = [20,20,100];( r+ g, \6 y( t% H$ `% [
a(2,[5 6 8]) = [30,10,40];' E! S2 B' v8 l( \* f. n& E( h
a(3,[7 8]) = [10,50];3 i) l0 _. e* Y$ L1 \
a(4,[5:8]) = [20,10,40,5];$ u" H P( \, Y# o! r. K8 y
a([5:8],9) = [20,20,60,20];5 g% W+ i, v* y, G+ y6 ^
a = sparse(a);
, p! c9 n1 X, t3 E, W% h[b,c] = graphmaxflow(a,1,9)/ H* ^5 I, e9 H$ j( e, {
最大流拓展:最小费用最大流 仅仅是在求得最大流之后进行对最小费用的求解: ![]()
" R) j. _7 V3 D/ B L* ^& R( Hclc,cleara = zeros(5);a(1,[2 3]) = [10 8;a(2,[4,5]) = [2 7;a(3,[2 4]) = [5 10;a(4,5) = 4;a = sparse(a);[b c] = graphmaxflow(a,1,5)
8 J' d7 I, b D+ F* i; Y最大流量为11 自定义Matlab代码: 0 N+ H2 o/ U" P$ |
5 \: ^: J( `9 Q4 a6 q0 j( ]最小费用求解- G; ?1 [0 |' C5 n6 V$ y
g, }- x$ G% Q, C2 F2 H7 uLingo:
! }6 B$ C/ n2 A1 y/ q$ Y" n3 R0 `6 f- P6 n
model:
% v$ q* v4 X% m: h% ^+ csets:% \# |. h8 |5 L6 M6 u0 l9 `, Y
nodes/s,1,2,3,t/:d;: L t( L* g2 [, u. Q. f
arcs(nodes,nodes)/s 1,s 2,1 3,1 t,2 1,2 3,3 t/:b,c,f;- ^" t3 |5 r! t# `0 I2 s6 Q% z
endsets
+ ~8 J! H- U$ tdata:
7 o3 { p& h0 V: S; Kb = 4 1 6 1 2 3 2;0 _# a0 c, f: m/ g
c = 10 8 2 7 5 10 4;. L$ }! j( v. Z1 ^' q$ Q M) c4 \
d = 11 0 0 0 -11;
6 u8 Y( M+ K+ J: f6 _8 n7 t* }enddata
' A1 G# n) O) ]# B N, q8 `n = @size(nodes);8 l: d9 X5 @( D/ [) `& e2 s
min = @sum(arcs:b*f);! R9 {4 ^0 r- F" J D7 Q( q" V
@for(nodes(i) sum(arcs(i,j):f(i,j))-@sum(arcs(j,i):f(j,i)) = d(i));7 Q d N& P; q: a( m
@for(arcs bnd(0,f,c)); ?, b! Q/ K/ A4 s
end' w! V3 }; z: `$ B5 [
1, Q* \' C f# o7 |
2$ s b+ Q! r" f" w% x. m& M( B+ h
3
, ^. I" Y% z$ ~/ E! K& y" X4) W; C. a7 P# U1 n; g- N, C7 Z6 \
5 ~8 `/ X. c5 h3 ^; d' U
6* E: j( c. ]5 k! g; b3 Z# _
7/ c4 O' k! W0 j# e4 Q c* |
8- I+ H% E4 c# }/ r' }
9
# t# s% \) J; x" s' I6 M10& {5 G; s1 u2 X7 M, I3 ?2 |
118 i* n; i- F* r- [. M
12
$ n6 |0 f B {3 e1 F13. X4 R7 ?- J: q' T0 x
14: {8 x; h3 s, \* w1 b
15" o+ b6 n% K S I3 M
Matlab实现: x; [. C' C5 w
0 v$ A! v. P3 E
: k& _! {! q4 W5 [
n = 5;* v }& I; {1 h7 C$ Z$ D) a0 v
%弧容量
7 Z- ] g* L# J/ F" ha = zeros(5);
7 _6 b$ s: c" Ua(1,[2 3]) = [10 8];
) i' B' I7 C/ Z" la(2,[4,5]) = [2 7];1 U9 E" a7 \" U! Z6 b+ [
a(3,[2 4]) = [5 10];8 n+ N8 o1 r9 {4 N6 K- _
a(4,5) = 4;
5 ?9 a& r2 R! T7 G. KC = a;+ [5 a S# z6 [; b% n' f( w! V
%C = [0 15 16 0 0;0 0 0 13 14;0 11 0 17 0;0 0 0 0 8;0 0 0 0 0];' j l* l+ f. q+ I
%弧上单元的费用7 k( {( f0 [( r+ B p7 u- H/ z
a(1,[2 3]) = [4 1];& |0 }: R4 X- j. f
a(2,[4,5]) = [6 1];( }5 L+ d; s& i& r1 Y# h9 U9 L
a(3,[2 4]) = [2 3];
6 U r/ N2 V. u+ v6 na(4,5) = 2;
9 L0 \% Q6 l- Tb = a;6 m( a8 R: K" S; j4 }" \
%b = [0 4 1 0 0;0 0 0 6 1;0 2 0 3 0;0 0 0 0 2;0 0 0 0 0];
+ m; G" Y% G! ?) `/ |%wf表示最大流量。wf0表示预定的流量值
C7 _" K3 F3 g! j/ A5 M2 b9 w n" Pwf = 0;- P- {7 }5 Z& u6 x0 S- |
wf0 = Inf;
5 E: C7 ]# O6 p4 b1 c3 }& I%取初始可行流f为零流
# ]/ Z2 f6 e' u6 ]+ |for i = 1:n
; O$ M7 X# H+ g& K! G- \+ ?3 j for j = 1:n
/ v0 z9 H2 _+ n, T f(i,j) = 0;
. {0 y% ^, `# |9 I end
/ Z+ S) t [: |9 xend# a9 ^2 A! K. ^& {
while (1)$ T) I* Y# E W$ M& m+ z
%构造有向赋权图3 d* W' w h8 X8 ]2 R/ M
for i = 1:n# k# X S$ L0 ^. A( o4 L
for j = 1:n* C R" c R5 j0 m u. O
if j~=i
& i5 s1 e- m7 D: j Y a(i,j) = Inf;# ^2 R% x0 t# G' \; g$ A3 o l
end
! [9 S% u. w% L2 x8 i: { end
6 L0 e% ]# x. H5 [, S0 d end
. ~7 j; R9 Y6 D for i = 1:n- z; C- D1 z0 U' }2 F
for j = 1:n" }' [6 U& N6 F) U9 J2 [5 ?
if C(i,j) > 0 && f(i,j) == 0* \: d* M# B, y* p
a(i,j) = b(i,j);
6 ?# u8 O0 Y% \& s* x' e elseif C(i,j) > 0 && f(i,j) == C(i,j) ^& {1 r( M' _5 J
a(j,i) = -b(i,j);
- c: R7 z/ b6 Z# w/ S" y, { elseif C(i,j) > 0# X, d) P3 j: m j, g# Q
a(i,j) = b(i,j);
. D1 [0 [# I* r0 ?& f$ M$ S9 R a(j,i) = -b(i,j);
# ]- S7 z7 D- x end6 }% N8 y6 G8 a0 n* v3 b% I0 E$ Q
end5 X Z j7 I: S; g2 I
end
. ~6 l, C6 ]. f- k. X, W' Q- P. z %使用ford算法求最短路,赋初值' K6 Q* g- p8 q! j
for i = 2:n' x, U6 ~( P& i% I- U2 L$ f
p(i) = Inf;1 d. V7 I& |$ M2 h. m& T. U
s(i) = i;
. W5 k f" y a# Y( F6 E end
, W" W6 \4 ^7 f E4 A: e %求有向赋权图vs到vt的最短路,赋初值" u0 L$ _- E n" a
for k = 1:n$ M8 ?9 S' U# d5 ^0 t0 H; X" k7 j
pd = 1;
6 N; L* H0 p8 B( f, n for i = 2:n( O$ }& \( m5 a" c. v
for j = 1:n
) S' ` i6 R+ ^6 ?' \ if p(i) > p(j) + a(j,i)% {1 I7 z' {8 H8 b; j
p(i) = p(j) + a(j,i);
" T1 a, W: R' j7 j" u" Y s(i) = j;
! A0 R* F$ v, p' \& G2 j# d! }6 Q pd = 0;
7 A$ r( z1 o: T2 k. r end
0 f6 j! P0 S6 W2 T" I end0 F6 [ Y5 F* {/ c% Q
end
- B" Q3 U' O* m2 s% B- J %求最短路的Ford算法结束
& x) R$ e2 G- c o; j' ]+ t if pd
( R R3 G7 b" R E4 s4 Z break;
: V1 I' ] n4 d2 ]: j end
( `/ u* d+ U! [- K) `6 o5 |- u end
3 w; c) o+ q, y( F %不存在vs到vt的最短路,算法终止,注意在求最小费用最大流时构造有向赋权图中不会含有负权回路,不会出现k = n
+ D: s z2 x( f- T4 h" f if p(n) == Inf
, G. |3 O Q$ X: I' B break;
- T7 Z; H1 E2 J! W& c4 J3 j end4 b6 G; P$ A, _0 t }: ?1 D
%进入调整过程,dvt表示调整量
5 q( E) b7 }: m% r0 l dvt = Inf;
e- P# ~4 j" L dvtt = Inf;6 [3 X- m, }5 g' G
t = n;6 ]* n: i/ P) V6 u+ O! F; q( o5 D
while(1)
, y) t; ~0 f3 h9 k( Q7 g5 b if a(s(t),t) > 0% G* _4 e+ M& ^# p' x4 z
%前向弧调整量
3 h1 \3 K5 U8 s6 P/ \ dvtt = C(s(t),t)-f(s(t),t);
% W5 W" p3 @2 Y1 Q# ^4 j3 d- W %后向弧调整量5 s. o& `# W' v+ }& r d9 V
elseif a(s(t),t) < 0; i9 S3 A. g) ~, V, }
dvtt = f(t,s(t));
/ t. L7 q( d0 p" ^0 O) m end0 q1 O% m- \5 w% z( ^
if dvt > dvtt1 T6 v: g9 o. q6 e; P& \. [
dvt = dvtt;
( l6 J9 ~0 h1 F* I4 t2 T1 Q end3 o+ {) N G* h. q% g; F: R) k! O
%当t的标号为vs时,终止计算调整量
+ {! f8 n6 d9 c0 d' z" w* ? if s(t) == 1
6 E+ N, u3 O) ?7 h: L3 N2 v: A break;
0 X* D) @. j! H3 K3 N$ e end
6 Q% ]" V# W! E% w %继续调整前一段弧上的流f8 e& M; o* @( Z2 A& x0 d2 t
t = s(t);
9 q. w! C2 g! p7 F end% d+ k' l! l3 b+ I0 w% _$ t
pd = 0;
~. o' H* j5 L %如果最大流量大于或等于预定的流量值2 ~; t' t, s) U
if wf + dvt >= wf03 G$ T4 l, ~* \& j
dvt = wf0 - wf;
. o) f/ X- k" e& i) x pd = 1;$ g% ]7 n) W+ Y D
end* f6 S$ e# S' e5 o! i% P1 H* f: e
t = n;7 }% }3 m/ G, w7 G# Q5 P+ Z
%调整过程5 Q! R. ]7 d# A" W5 k2 y4 r
while(1)' ]- Y' ~8 b5 p" X& l% K
if a(s(t),t) > 06 k+ k: g3 M7 r! ^0 \* Y
%前向弧调整
1 ?8 P# r8 y+ l) p3 H f(s(t),t) = f(s(t),t) + dvt; % \8 @8 i- y- o ]3 [
elseif a(s(t),t) < 0
( ]! s9 i0 A9 c2 S$ b %后向弧调整
- {; R' u( k" i0 D4 ]! ^* p f(t,s(t)) = f(t,s(t)) - dvt;
; o$ \6 @& z8 p( J: o, w end
/ ]6 ?2 k; }/ ^ %当t的标号为vs时,终止调整过程: e3 f- w: b* L7 A9 ^
if s(t) == 13 c8 u R: ~9 g7 [) Z: q
break;
) @5 I+ g& G c0 U9 Y end
9 `8 p8 Q+ Z2 l2 p0 W& L* D t = s(t);" \8 o1 f7 Y: g; e( s
end
6 e1 ?' q p# o+ `; `( I2 S %如果最大流量达到预定的流量值9 F. ?3 V5 S& u. Z/ F, O
if pd
* o* t8 N; k8 i. l break;
( O8 c' I! m$ ~6 l! @, R* o end
7 f) ^) I6 l, C3 F$ T %计算最大流量0 f6 u6 t S N k1 m) A4 U. B
wf = 0;
' D/ @& C. u* t+ Z0 V: t Z for j = 1:n
+ b! E& W3 M4 A5 B+ c wf = wf + f(1,j);
+ E% ]' b5 E2 Z' n- Z/ l end5 J# y, ]: ?2 K9 z; T! h/ K- B% X
end
, V1 P# d9 N) G, y5 c3 e%计算最小费用
, W8 ~' C( ^, q7 a: d5 ozwf = 0;
6 O- E8 t! j$ h/ [( B0 rfor i = 1:n1 g2 p' A: P7 l
for j = 1:n, B' p* a7 Y. E% A' ]- x& G* `" b
zwf = zwf + b(i,j)*f(i,j);% I l) k& a4 Y( {4 R% O
end3 Z( Q) c& j) }/ m# |2 y
end7 m) ?, b: F' s9 i2 w+ i) E/ G* X
%最小费用最大流
6 ^6 Y$ G/ A' ~/ P7 s1 I, If' d# `- Y/ y0 j( z* h- B2 \7 P* P) C) r
%最小费用最大流量
3 r$ I6 H/ ]+ R" A7 J5 ?wf- [& C8 R2 {( C7 N) d
%显示最小费用0 {$ Y! q! g% ]0 L
zwf
6 r6 t) c' M( S* g+ ~# H6 m1
9 U, D8 \* | G8 @22 f9 d9 ]- e* m+ [) j9 o N- |
3. Q/ `+ G; n3 \9 p1 s* P5 a
44 {& u% h0 f: p3 C( p0 S
5
( v% C1 v8 e: I# i+ d; ?63 A/ k6 v2 t1 n5 m3 U' v& r5 y, F
7$ b' Q+ S- l' c; I# e {
8$ K! J. b0 p! f ]' {/ v- E+ X. W0 }
94 s! W7 q6 H6 P1 Y! q' _1 }; z5 E
100 r, e+ I2 k: n {* T$ C
11
4 J) `2 Z {9 p% G' L1 p12" N8 d2 T' V0 d/ b
13$ S# R% ^, n2 x! A8 q) n
14
/ F* \ h7 h* o8 a! E+ `6 k15
/ S) D8 W7 F# R4 W1 M8 k16- k& ^, R4 i: I/ T
179 H6 [# d! n# s& z& m5 a$ \
18
( E+ o/ h4 A3 D/ u19, |! @0 u3 ~/ I n
20: t6 ~) J0 |+ U% s1 ^, ]1 w8 l
21
% o( t8 G1 `6 m1 b: {22
' }$ `/ j1 w/ ~6 N230 [8 s5 I; |) T8 v, @
24
7 ]+ t b: Z- s$ A4 L9 f& S25; V3 X3 R) o+ a+ d/ s$ v9 N& W
26+ ]( F, _& Q2 T: [
27
& R- a; V9 Y" h6 g& U) ^28: c# T2 {$ S/ v* b9 }/ R
29- }7 P$ ^! Y. [1 c. `
30
- v. l; \7 H7 J) `315 k' T/ U9 v3 h( a2 h& u
32
4 o5 O# R; `; d& `9 r( }; Z" P3 U0 F33+ J" i7 Z( V% p3 q, T1 S1 @
34% o& Q5 \% {$ n
35* Y7 M, j: Z! G. ]$ A
36
. L& E/ P' N f37
0 Z+ P0 L9 O2 f, l38
: P5 j$ s' p9 S4 Y393 k2 D& y! Q- ~( `9 b4 o, }5 z2 E
40
0 O; J- @& ~1 Z+ g' O; m) ?41
' k% c6 d8 c w1 n2 L9 ?42
% R# d u7 ^' C( K6 |432 r8 K" ]8 C$ C' {4 G. |$ _
446 Q l. G' ?: X& a
455 i7 |5 j5 e4 ?5 i- a7 K* {6 ?
46
/ L; C; [; R5 F+ L0 g, R9 O47
, Q5 a0 _, F9 Y; j7 f48' `) ?; X& ~4 H3 z) \/ p
49: g; e ~, B. T4 W. P+ u$ R
50
3 I' N+ u9 b( e1 @& C9 \51: A9 D7 k$ M; v5 q" m. D0 b5 x9 H
52
}' v# g' U k1 a5 B53
4 Z1 ], y; L$ [: G+ C/ M) @4 t54/ h5 ^6 [ U4 [. z. M: K
55
7 u$ W9 [# L* [2 `# s& ~* F56
+ P0 }; g3 j8 ]2 b57& e; r# F& \. N, \- y
58
8 f( e' \8 h, U. J% z$ C/ T59; ]: l5 N( H- c; r8 o3 o
60
. `8 {7 y7 V# W& ~+ ~61) G J: L7 W! Y% x: ^
62
) E; s0 n0 D, i& u63
# e8 ^. z7 V s64
! r h$ o" K3 a. g' B65
( `0 P. a% L4 k; C! s66
* W# k1 ]$ x8 H% X( J4 ~672 H2 Z$ f5 R* p
68
# Y; ~& \- B% c* K* n/ P( e1 F: r697 k0 J# l* T7 t: b8 o
701 R' G6 R ]) y" L9 Z
714 B! A, Y8 ^3 j
72" F* ?4 _/ D9 h* D8 z
732 q- m' C' L$ v; ^7 [* a. |4 a
74
% ^, H1 q& [$ `4 m9 b75
. k w1 b0 a1 W% p76
, Y) q; L; X% Y, U7 g$ h p' q775 X% b0 L$ U( o: i F: |, q- o+ U6 l, x- a
78
$ m; ~* w% B& y796 A! n1 G0 r5 D# a. E
802 k. x( |! |7 r% _& T* _. \0 d
81
2 N1 L2 O, ?9 l82
# ^+ I; y/ m# d7 D" @' ^( _83 i( V1 }0 \' Z
84" q9 U! [6 E& S- e; `2 S: N
85
7 J6 e* r! @ r; ?+ `" I86) w% q1 b: D+ Z" u- d' G: c
87- G' y; h0 y {7 c
88' _% W: h- v: X- [/ [$ U4 U
89, @3 F; E3 e# W$ K
90
/ S7 |' a7 U+ i91
% n/ u5 \8 j! S$ b' o6 U92) ]" e& K8 G! q/ b3 b: z" [
932 w V! u( B" M& T* j+ N2 Z% g. h
94
0 t& U6 n& Y7 c( {5 ]9 V95
% B9 F6 \2 ]' [4 b) {* i96
7 T: w2 h: Z, y& \6 R5 Z97
9 C- y4 z; |: V0 K98
% t' U2 F0 y, b; ?8 e# r. d% B5 Z# K( |99
& C0 h# t: W9 M8 S+ ^: G1004 o, Y5 B4 r- Z6 q+ q; B
101: E0 |2 B& B* l! ]% q1 K; T1 Y
102
: t+ f" s8 Z4 }$ B! R8 k" i! v103
' b. E2 r( R( Z3 _& |. W0 J- r1044 I. ]' P1 z$ ?
105& h9 D. ]3 u. T' X& e& _) O
106% v$ t3 Y$ t6 E- Y+ s/ P( A
1070 G; s% c/ g) h* A8 I% ]
108/ {* e4 T4 E" n8 r& b
109
* f0 n/ K+ |2 i. M6 L* g110
* f2 ?) L0 o3 \( H111+ y2 L8 T. s3 x G
112- s0 ~; {+ m8 K4 e3 S/ g! F$ s4 v A% G
113
U) O) N( C5 i+ r" g: M7 V W z1146 m) d, X% u* W/ p4 a
115
i/ `8 U# J3 G: K116/ z% S$ z: }7 g/ c2 L2 k& d
117
! a8 f: M" K4 k! S118
* @ w& u0 W. u$ Y( v119: }" Z# F# n- |6 s0 c
1207 K K* O! T! k1 `- _" x& A* ^
121
7 r8 y+ q" d' |/ x+ k0 U3 p% Q% r122
9 i* H+ L+ w! \' u- O3 B% M123
9 a' C* ]& ?2 L# h124; _3 g. y, P' C6 a- k! I; P# I
125* m" T) [" x! m' K6 m7 t h, G
1264 O: k. _$ a& }0 Y" n: b% v
127! v: K: A! B/ @ Y( b
128# M1 J( ~; W) r p
129( P3 A4 A( k: U2 w. q. }7 d
130' O5 ?9 @0 _% T2 x+ R
131: G8 q; o: r& W# g
132
) e. d; c$ l& j+ s$ ~! T( y133
2 \- F+ `2 s( V4 X5 P7 i( @134
+ P3 h6 m' a/ T0 I8 t: ], c; s135
& ?4 [8 ~+ c; j2 B9 u136
& }+ |( i$ x0 U2 ]* a137
; v3 q y" m' ?$ I( Q+ F1 M% C( h138
: X- a \. k# O" k, y7 s4 O139
, x+ O C: r$ d$ n# `) F$ l8 P140. @4 ]! v* `9 e% p' o" C& ]% I
匹配问题:8 A ]) b9 o% k4 s1 c
" W7 m4 h, `% \最大匹配:
7 [( ~- _: S2 L% w & {: l( k/ q$ M* L. D* j
, f/ c4 k& \8 n) {
代码实现:
4 `/ {2 v4 p# [* @6 d+ T2 s
1 ]( c: Y+ l4 B& Um = 5;
2 A d0 u J7 [7 ~( s) Cn = 5;3 S. p9 _# j2 Z, g% W
A = [0 1 1 0 0;1 1 0 1 1;0 1 1 0 0;0 1 1 0 0;0 0 0 1 1];+ |, [' w y7 O8 b. B, o
M(m,n) = 0;2 g: P* ~( t) U3 q' q# m J
for i = 1:m$ z; d/ F/ a7 B' g" o+ O1 u7 o9 o
for j = 1:n
$ v6 h" j) }1 J9 T# \9 f: i %求初始匹配M* G( C$ _" B% }2 M2 S! X- _* ? h
if A(i,j)
( _" J! O/ V/ t- e7 M M(i,j) = 1;
# G: |5 O+ }; W5 \/ b1 d+ _, \/ a break;0 N9 n" ~' n, S3 @3 ^+ _1 w
end
$ v. i( ?- {3 L4 t4 J" ] end
0 U9 B' [4 E2 R; T% \& D %仅含一条边的初始匹配M/ n0 G( U$ V- P, f0 R' T3 x* K9 i
if M(i,j)8 u& _4 o" n6 J4 r3 \) I
break;- Z- F6 P T# B6 Y: a
end0 j, e, d- Z1 u7 W- y* E0 f2 K
end
) m5 G' ]; T; u' `
" {; W6 o: A& v/ }& P' vwhile (1)
8 {- S" H. n9 k4 T %记录X中点的标号和标记: V$ S2 p/ v$ G1 o4 T3 ~6 e, E
for i = 1:m4 V% |( N& A3 {, h- T9 F v
x(i) = 0;& {2 T. o U. H. ~) A2 Q$ @: |% b6 j
end5 c2 i% j* F4 Z, y$ W
%记录Y中点的标号和标记: P" y' e. Y ?* Y' l/ ^; B1 c
for i = 1:n
" `4 j* K# p6 A7 l0 N5 b3 P; K y(i) = 0;
0 k \8 o* ~/ l" n- ^5 Z/ N end
6 P8 Z/ }/ j9 A+ |$ c7 z %寻找X中M的所有非饱和点
& d5 s2 g e9 ^/ A" h) x for i = 1:m" N g& s4 Q5 D' e4 K3 e
pd = 1;0 r( p- ~( z( c6 M3 `9 v1 g7 w$ Q7 L; I
for j = 1:n# E+ y1 e) n# H6 k, d
if M(i,j)7 `; d/ ]. [3 [
pd = 0;2 p( x0 J- J. b: l1 D6 d5 M
end9 s9 p% _2 Q: F, e, c
end* t% k+ _% g6 C! K+ D
if pd
# W3 d3 v" V' J7 c2 o$ m x(i) = -n-1;" x( n( _* L+ F* H2 c
end1 l5 I, X# [5 [- ~' Q9 k
end
3 U- z6 r1 t- ^) k6 e8 M pd = 0;
2 ~. \1 n, |; W& L while(1)6 B) i, b8 T0 ^/ \
xi = 0;: t7 d; [7 e& A0 s
for i = 1:m
0 R5 W' a: S$ c8 Q if x(i) < 09 z% e0 \# p6 q" G/ b/ b4 k
xi = i;
5 y# ~4 w% T# S7 W break;1 v0 {- N8 L& z& o& W
end, B: ~$ `" f1 \' F; U" o" v
end" a6 g- R7 [5 g2 J# c
if(xi == 0)0 W1 ~3 i2 t- }/ J
pd = 1;8 Z6 w' }5 M8 a) u
break;1 h- A, |% j; D. @
end' o0 @5 S( y4 n
x(xi) = x(xi)*(-1);
1 F$ {* Y: ^7 v2 _9 z% m k = 1;& ^) Y$ ?/ j$ s9 ?
for j = 1:n C) T1 X% v$ E* o& |; t- O- n
if A(xi,j)&&y(j)==08 h3 _% s& s# e# D, A3 Z2 h# `/ ?& W& u
y(j) = xi;
5 H* W$ N/ z) k* u$ p yy(k) = j;
/ R; [; X& J' U, N( g5 @( m2 h k = k + 1;
# Y$ Y: b* s- J2 t4 q* J& l end& y8 P V$ E! Z( }% {; F
end: T# x D3 t% ], C9 N+ f+ ^; q
if k > 1( ~% q0 _# E; D7 r1 |) Y. ^" z
k = k - 1;
@5 s0 U4 D# O for j = 1:k) z( I* ]% u7 M9 ?' |% n7 G' ~- ~: k }& p1 k
pdd = 1;
# H. ]2 R3 n1 j3 L2 a for i = 1:m( n! o G% ~( a+ Q R: q
if M(i,yy(j))
, X d* a8 X1 w: {2 P x(i) = -yy(j);" n& Z# l" i+ w' n- y9 r& |8 {
pdd = 0;4 l' W# h( ^1 }3 E6 y, ~! ~0 }6 ]
break;0 R( h P1 J2 ?
end( L o( X, [& j' \# c$ B" L8 X
end
- c' B9 f% w/ I* s1 G: i if pdd
' e* L, H. h" I' @ a break;9 M4 C) w# _& Y4 A
end
! D3 n9 w: B& d' Y& c$ R% A end8 \. V) t+ E' z+ y8 s) U1 f
if pdd
4 A( R& V! N; e% [5 k. L k = 1;
! O9 `- Q! S# T4 Y& a* ~ j = yy(j);
Y1 S; R ?" s* X) { while(1)2 _. B, u8 T) M# q4 j, Z4 p' y
P(k,2) = j;
" ^0 T, i' V; a P(k,1) = y(j);2 X7 G+ G/ M9 F4 x
j = abs(x(y(j)));. O6 R' `+ ^2 x6 `( I; d
if j == n+1
5 Y' s2 x# @0 H3 r+ C- l' h- u8 l break;
# A/ Z) Y. l( s. H3 V$ u: M end
; b! ^. l4 [( [% B- ?8 J+ m9 x0 Y k = k+1;
a- q( k' x. S$ b/ `, G6 B( _ end' B% D& I1 K& o6 ]4 a
for i = 1:k
# u" n+ M3 i- w if M(P(i,1),P(i,2)): K3 i& w p6 l4 p7 Y+ v7 G
M(P(i,1),P(i,2)) = 0;' U; O: Y/ b# x& `: T: j
else
2 k9 A) C2 j/ E+ Y* } M(P(i,1),P(i,2)) = 1;
' h1 m( y; T. m _ end
* S1 K/ Z$ z5 q. e8 _7 A/ ^ end% b& G% k! m2 e- M. `, p
break;6 }. H" Z0 m4 R, f3 P T
end
9 h0 \5 D! I+ ^7 W end. B/ \# k) e: K" v ^
end/ c; g; n( H4 ?& g4 [% n! `9 v
if pd
, }) u4 R# C/ n& O y% M) ?$ s break;
2 d- ]* k: x" Z3 L end/ _9 u3 b( k/ T1 H$ d% r1 a
end/ v& Y- y( V* s" f X
1& p! h, C" Q i1 F! S9 T
2! A1 I. ]2 |0 t4 p h* v) J
35 C1 O) @) T _% T7 U. b
4- h7 X; g+ Y, h% {
5
( X7 H( ?* I# n; Y8 u+ J" g69 o: W! y- R) J+ Y! q* r1 n7 \- J
7
5 r* { V1 X' x- {, l6 S8
5 ]( H( {$ F; o8 x# {+ i9
. m: b: A; L! X! o4 ~7 G10$ a) }& t' Y, y; y4 A) j" c' V
11' d5 V! Y& c" \0 a6 S7 W/ J4 X
12
B$ c7 {$ |4 Y13) X* E9 b! {0 T, O" b0 ~( @; g4 A
14
# K$ U% a' c) H* Z; C15
+ Y+ Z& W2 `2 x, m# L! J. \16, D% R* e+ a) g; `$ Y. d2 r
17
) l. W* b0 d7 Q/ d" G }18
1 o: E; ? H( [, Z* L7 m& N19
5 q8 H7 E; L5 z5 Z# M20
) |: U0 k5 m* y( X) c v9 J21) B) F* q% Z6 O1 l X1 r2 a
22. {# q' I f, V2 M2 Z
238 h7 M$ i. F: M& }' s( ~. U: t: o
24
' y8 @. z9 V' p& u a: s4 ?25
0 T" d" u* w' m$ J0 N8 y9 q26( k* k" x7 M5 }5 J# W! c
27
: e) H/ o) y/ k$ ?& W' l289 U$ r* c7 y2 ~5 a$ @
29 Q5 e! h6 v* i- U- n2 O% b
30: o7 z+ |& B8 W& V: `% ~
318 n" ^% d) o4 N! t A
322 `* M J( ~- d5 U7 I, h
33
0 N+ }1 T1 M1 e34
" l" I; {3 |. f; }! T# `( P1 {7 C35
, O- s( l/ ^ J6 @' ]7 b, X36) J7 h: ^8 q8 u$ P. {, T2 `4 `5 U [
37% f6 C$ k, @( U3 o( a
38. @& T8 v5 c9 D* X6 z+ S+ h
399 U+ G. Q }5 B# {& j/ V
40
, B7 m3 T- |0 S( b414 \8 N* E$ o5 b- h" P) a% s
421 M, c& L! V8 a* u. b
43
: }9 M% g6 Z8 H$ b& o449 N. j8 a+ T2 r: Y9 a% f( s
459 a. @: D8 u. {3 V6 B
468 N0 t% i6 n0 x: d! x
478 Z2 l. ^; K' W6 v
48
% h- M& s- M& w( }; E: Z4 p7 q7 A497 @0 h, h$ y {& L! f& C0 L2 o9 s
50* C' f8 ^9 f. S3 k
51
2 e7 X4 r/ _& P2 f3 j' s525 w6 T4 }8 w! S! S: M- O1 P
53+ t" z) j) A/ |! W B% e
54: X8 ^8 X6 @7 K1 m) r2 f
55
+ i h; F, t5 }6 F/ k6 M1 t56$ k* v7 w, c! f9 X5 l0 B0 T" j& L
57
, l* A$ l1 w7 u M- G8 a3 |58
8 ]& L* ^1 i, H7 |59
* Q) B& X: f C. q I60& D9 L" ]6 ?2 g: |% t
61
3 j) @2 x' T5 p' ?# D& f62$ \" x3 Q/ b& l9 i, ]
63* b$ Q, y. U: O4 F# U$ \
64
* T8 X0 `$ l2 f- @& I7 x7 D/ p65" w$ r- w8 a5 [5 G* T/ w
66
* a2 w. {" @9 t( J, n67) R. c! o, Q3 k4 s1 O/ N# {
687 ^ m3 P- y, X5 D
69
& K7 N0 t+ v# V70, p8 ~4 i5 [3 J6 Z9 j- x0 a
71
( y5 D, t7 D/ o3 L0 q! M72
6 O: x9 s" I2 h: S9 v% x739 O9 h1 H0 V+ d
74
- Q" @ e- y" C75
6 u) E8 _. d* I+ q- d76+ Z) [; k7 ~" E! r: \7 m0 [
77
3 w7 s+ u7 w. A& Q, l$ t. w$ s78% ?+ U" D+ Y+ O8 C/ q, K5 r
79
* P8 e' @" j( R g80
; S+ W9 e2 ?- N# ^+ w81
$ T9 Y3 b/ e$ ^3 X4 z0 A82
9 G; a* s1 `$ v836 N/ b" }" C& K$ E& O
84) E$ w# @# Y+ X" L3 x
85* _- p0 E6 C) B
86
2 u/ [! d; _8 R5 |! ~87" B- K& @# ]: Y1 u1 j. R6 P8 ?
88
3 Q" C4 @8 C" k89
0 X" _, ?# i) }+ s4 @90
2 z" d7 T! H5 m7 R, b+ R8 V91 \7 ?- j2 k8 n' J% m% k
92% a7 W7 @) n5 m5 `+ y- f
93
" g' I- ?1 y. n94
, }/ O2 c3 T$ J! o% y2 B+ R+ {95# P( G9 l8 F2 i1 ~) M2 E6 D1 F2 u
96
2 i' a# y& \6 o4 E97! F. |3 `9 m9 x5 L6 T/ Z7 I
98" B5 _% G+ d b9 X
99
0 K+ L) W" i0 w/ g5 g K! f; n100! S6 `5 Z) ?5 E0 j, p
101
( l/ F0 m( W6 h* W6 t, R, P1025 f# y, G9 W1 U/ h5 d
103
5 K+ `7 l) s8 t最佳匹配. X) _$ S9 I: _2 C; M% x) ~0 o! \5 J o
" e( R* G* n, s9 o& F6 J! Q+ p2 c
代码实现:
5 X1 i3 t8 V5 j- J6 T r( {' T6 _. q6 m1 @' g+ W0 K' u
n = 4;
% l5 d9 T+ z& m& a; w$ q2 Y3 DA = [4 5 5 1;2 2 4 6;4 2 3 3;5 0 2 1];
8 Z# _, e3 M: p1 I; yM(n,n) = 0;6 i& @0 J% D9 V/ w$ D
for i = 1:n+ t. h4 J9 z, o% y
L(i,1) = 0;
/ t O& K! Q& J. E; F* a, ^ L(i,2) = 0;! b4 D7 ]/ G S; h+ l( [9 i
end4 U. D( S' k+ u# m
%初始化可行点标记L
; {5 p: f# Y# g- Efor i = 1:n
& k3 u. H: u: K$ v+ o for j = 1:n0 K5 ]1 {5 Q1 |- U' y
if L(i,1) < A(i,j)
, l/ m( K }# G6 h' O+ S L(i,1) = A(i,j);
4 U& I8 f3 Z/ c end% y4 }* R D8 d& u$ W0 E: D- i
end
* Y1 S W5 z1 Kend# R4 W4 [9 L, }+ G$ f) j Y( ^5 a3 m
%生成子图Gl
3 I$ V9 P, ?$ l8 ^: ]" q* Hfor i = 1:n
/ d4 R4 ~4 o: P' u for j = 1:n
8 Z+ r: T0 Z" V2 U6 l if L(i,1) + L(j,2) == A(i,j): n3 x2 G- D3 l5 F( ~
Gl(i,j) = 1;
, S& h) s) U" U# R9 F; p else9 v8 E1 \. ]9 D: M2 T2 W5 q) ^
Gl(i,j) = 0;8 J: ?; o; F; p
end
" Y. {6 U, ? V q end% F/ D# }4 _0 B$ p! u+ j2 U
end
. Z9 }% Y# T- X" B1 d3 j" [' g%获得仅含Gl的一条边的初始匹配M
- L& W: ?3 l9 u. V. Jii = 0;6 \; U2 Y) g7 p. M" n3 {
jj = 0;
; E& Q6 [% l) z4 A$ L A. Dfor i = 1:n
* c" |- i, D# X for j = 1:n3 K8 y$ c( M: l* j5 }7 g! r6 }+ \
if Gl(i,j)
3 R5 R2 y2 J6 O4 T ii = i;; c1 `; X1 p; q& |
jj = j;
- x; V7 H' p* e9 F break;7 w, y, E/ T$ |* z% c. {% P
end0 {. B7 Y" k, g' E; F, k6 O
end; Z( Z9 r5 x' t k! {6 V Y6 B
if(ii)9 f* a. H) d+ U$ ~
break;, ^ V! P6 D9 | A8 |* v4 f
end
7 p# r4 T# J8 ^( l3 B9 }) f5 D& ~end
7 F+ z, I. k, x2 }# zM(ii,jj) = 1;
+ P- l& m" g1 Z p1 g; Z, a' q) n6 yfor i = 1:n) C5 b% P+ z1 Q8 o4 v0 i- k) R' V
S(i) = 0;
6 q' D1 n, L& O, d: @ T(i) = 0;
0 H3 T4 |; Y- H D( l NIS(i) = 0;
3 T% n& k/ O2 w/ O* l! N( Yend: d. y7 T9 i( B8 }% e
) [, [7 G. a" x: e4 c5 w' m M5 E* l
# V$ `+ R# F1 E3 ~7 F# o8 Dwhile (1)
; i( Q" q2 n% N: u g for i = 1:n
' T |) C; E" d4 k7 K k = 1;
) B6 z; r* ]% D S! L' b8 y- c for j = 1:n
6 ^. V% T3 v& F0 j if M(i,j)5 ~/ y0 ~- |+ l' o9 W0 W
k = 0;9 W5 n' h, Z& B! H# Z% ~
break;* w8 V+ h7 R7 y9 v1 S+ [0 [
end. u! q4 P5 ]& t: l
end
, R! T% [. L! _ i+ K8 w if k
3 H/ j' A. J' e" I' J8 m9 ]: m7 c break;/ L% K8 n% p; n6 P% P: e
end
9 w; u' O) |0 ^6 U* ] end/ `' K9 q& d/ @7 M+ a% R
%获得最佳匹配M,算法终止: E7 ~7 h; Y3 f2 B
if k == 0
7 K8 O5 v: ?$ W( V/ v break;8 W/ z' V: n* \6 R
end2 L0 l* l) i) f9 I" G% I" W0 T
Z: A# R4 {' [& Q! }( n5 i6 U5 \3 s1 h
8 I% w& o& l1 R% B0 \3 [4 r# t
%S = {xi}% q% f$ ` _/ j9 f; @4 ?% u) G2 p
S(1) = i;
8 m; m" P4 R, L: m& E" r. J4 Bjss = 1;
( n3 g, p+ r; V% z8 X6 g ejst = 0;
* M6 X! Y% W& z: Hwhile(1)* x$ b+ u- \7 a- V) i& Q
jsn = 0;6 e+ N k& g( C) f9 G
%选择NL的值$ B/ n7 n: {. @
for i = 1:jss1 {$ Y7 a' f* ?" W- R
for j = 1:n
4 ]' ~: [& z8 \' X" q if Gl(S(i),j)
# X! y+ [5 I0 P2 g0 A6 X jsn = jsn + 1;/ I) |: G$ x: H9 o! J' l" }, D
NIS(jsn) = j;
9 z* `2 k/ `, b! O. R for k = 1:jsn-1( e$ w+ [2 h2 V z
if NIS(k) == j
4 ~: d) w. d8 l jsn = jsn - 1;
8 ^# K: {1 W1 t9 _ end8 G- h4 T) R3 ?: R; `7 I
end
$ i( F! G$ L" ? T0 Z) R end
7 s" m% I& A5 A: H% {& u6 ? end: a( W( f# Q" J( r! ]
end6 U" z+ m3 U6 d; j( F) }, J a
%判断NL(S) = T ?* N) P; d! w2 B6 b# j2 Z
if jsn == jst
4 ~ S# e% o3 d) T& z& L5 Z. S pd = 1;
0 d0 H- ~8 n4 ? for j = 1:jsn
1 D5 O0 ?! v: t+ s# p9 O; { if NIS(j) ~= T(j)) Z( L( J0 B* w
pd = 0;+ u" p/ `# q4 S3 M3 b
break;& L, y# L7 [5 K% L0 j9 F
end
6 }/ m- f5 s- {+ L* ~ q* d end( s; U1 b& h. X
end6 y2 d5 R; X2 n1 S& U" M
%如果NL(S) = T 计算al的值& a, b, m7 e$ G, j) Q2 Q9 H4 N
if (jsn == jst) && pd # ~/ Z; F- D$ |3 Q
al = Inf;
# F6 m$ g3 C k for i = 1:jss1 ~! _' x( m% b' V; d
for j = 1:n1 V | q) Q: A7 H7 Y
pd = 1;
% ~+ A, ^5 p( ^ for k = 1:jst
- K0 l8 P, m$ \6 A4 P, N" T% K if T(k) == j9 J+ f( G7 U! V& P, r, V c
pd = 0;! ?5 N! I- \) a1 y& Z5 N! P
break;* E! R0 W. ~+ D4 W9 K' ]1 N7 h4 a
end
' A. ?4 N) F$ M9 ? end' z; i% H7 B7 _1 F; M
if pd && (al > L(S(i),1) + L(j,2) - A(S(i),j))/ @7 h4 \4 T) f3 v9 e5 b; w. I! v
al = L(S(i),1) + L(j,2) - A(S(i),j);9 a1 D4 o5 l& @5 p) n4 A
end
. Q( \4 f8 W7 G/ j9 e2 o( ~7 y end' L( a% n! }3 B, e
end
6 w% r$ C8 o$ W+ @7 s %调整可行点标记
7 `: o, J4 x0 t$ C0 d/ D for i = 1:jss, b6 Z+ |+ K3 s Y8 n4 i: T6 r8 u
L(S(i),1) = L(S(i),1) - al;
- A. l! W% b& q1 n; N6 E* b3 S end
( g( G+ ^( a2 x; t %调整可行点标记
/ l. N. C1 u2 z4 l8 o4 A. N for j = 1:jst
( o9 Y0 N3 m+ [+ n+ J/ C7 R L(T(j),2) = L(T(j),2) + al;
. H3 b" e( j: ?/ U end
6 J! O. D* L3 O5 J, p %生成子图Gl: r/ \9 J# j& }; _/ c" n8 M
for i = 1:n, N7 f( Y& l6 h/ `3 |- v. ^) l5 D
for j = 1:n0 c4 b3 Y" [/ q
if L(i,1) + L(j,2) == A(i,j)
1 r9 [" X1 z* f- ~# |. F# Q Gl(i,j) = 1;) e% d2 X: y3 D9 w3 C* S
else0 ]% l9 t4 m) O; B7 m7 c) r& X* L) f
Gl(i,j) = 0;
" H% B: Q8 c- _ end
% O, v8 t3 V# x8 x! e M(i,j) = 0;
) W; ?' i* f$ o% a( h k = 0;- E- H$ a, f% \3 U z* u
end+ B* O5 o$ `5 N, G, R0 @
end
4 I& d W7 ^9 f' U' ] %获得仅含Gl的一条边的初始匹配M4 Z1 ]" E$ a* t
ii = 0;
. P8 n: m% ]1 g/ d' i% j jj = 0;: v( Q: [% m: _
for i = 1:n
0 I3 ~. g3 V* i9 T, S for j = 1:n0 L; h; \* m4 T: F; _$ W; k
if Gl(i,j). R! @; Y9 W& M g
ii = i;
6 X( J& O. b5 p, z: w7 J jj = j;
8 [% f' V( B& L2 t5 v break;4 \8 B5 w$ ^; N! }& z3 ?# _( ]
end
) ]1 X5 s% i" @: k( N; |2 T4 \3 w end7 F0 y- B' u- ?
if(ii)
5 ?( `6 ?5 `( U, d break;
- N& Q, \& c5 C* q3 X* ?1 G L# q end s0 F& J7 i3 S5 U+ h; ]+ u
end# A" W- M' R, `0 P4 J
M(ii,jj) = 1;
+ k8 k7 m: G$ l" y! ?- n5 q break;" O$ c1 q v" M: |
else- r; z4 j) F. \$ E
for j = 1:jsn
. K: O+ F) B$ z- @4 m8 A pd = 1;( |! F7 o3 R- C6 D. x
for k = 1:jst
X3 ?; M* x8 j0 X9 [' b if T(k) == NIS(j)
* w7 A7 U/ v. f pd =0$ ?- i7 [! s* ^* {' n0 I4 V1 k& K
break;& X* g( u( S; s8 B7 }' q/ W
end
. c- e* f& u# R+ I% M1 | end
I ^, @( M! N9 N+ g6 g if pd
3 ?' o6 B I# L8 x5 _8 F" C1 t jj = j;* f4 |2 e+ x+ t$ |0 D
break;
7 U" g* P. z9 } J( g v; g, m8 d$ m+ E end+ T7 Z6 p; f! @- U: T S i
end5 }( L* l2 P9 n! m
%判断y是否是M的饱和点
4 Z$ B9 k: C' r8 G pd = 0;
( m1 ^" |# E+ I# I2 M" i/ @% U for i = 1:n/ c; S ~/ v& b) r( _* x
if M(i,NIS(jj))6 I9 u* ]' B9 t7 D" g% E
pd = 1;; S; j' S" U% Z" D; {" e+ H1 k
ii = i;
P, ?- F" o4 K5 A0 r5 f8 U break;% f2 m. z u* z7 n
end$ }2 Z$ o% x0 K# ]+ l( E6 d
end0 j. y' }/ g2 {8 ^
if pd" N9 _% j, i/ S6 {6 T6 r z( X' u
jss = jss + 1;( y/ G" x5 ?! j! y- i r* [
S(jss) = ii;; M7 ^* V2 K6 D0 l9 |5 o( }: {+ `
jst = jst + 1;
" F0 t6 L3 ^8 A8 z4 o; b, Q% M% m T(jst) = NIS(jj);( Z- |6 ?; F( N
else
5 J, q. h% w5 V4 T* b( u' K for k = 1:jst
" K7 `# c5 S T" x! Y5 @/ {. l M(S(k),T(k)) = 1;
% E( [) t/ m5 Z4 J1 w1 V M(S(k+1),T(k)) = 0;
4 Z* l5 c7 K' A9 O' n/ E8 \9 I+ k end
" X- _* h( \. O7 z6 w if jst == 04 O# y: C3 s* {( Z
k = 0;
" P% f1 X2 [3 W% L, `: G5 N end$ u. }! _2 g' I, f$ I+ _
M(S(k+1),NIS(jj)) = 1; C# H [; S3 M6 X+ R
break;
; @" z: o; M! T# W, o' r( | end
/ p2 W7 i7 j1 _) r& X0 i end' t# S: }) D7 Z' f# Y' J7 B
end9 L. I8 [3 u% g. X
end7 G; s' B6 x, h" c" H4 M
MaxZjpp = 0;" O7 R( S# H/ D7 v2 Y" |
for i = 1:n
9 I6 E6 f, Y# ?6 I `# c for j = 1:n/ x' Y( I: j. H$ E8 r1 R" q2 }
if M(i,j)" J, B; r4 I- s% b
MaxZjpp = MaxZjpp + A(i,j);% W2 x( Z% o* G) U5 @3 y3 w
end
3 _5 K. E) V- |' n5 l end
& v! w+ z4 r3 X+ \/ _% N end) T: B7 B' G u' k/ O$ @4 i$ S
M& x |: B6 h) S% M; Y
MaxZjpp. o2 I8 H" T, N& i3 @
% F- t7 m, J" h6 w& I0 F2 q/ C6 C, n4 V3 \
% V/ E& k" Y# f/ u# e
|
zan
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