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升级   79.5% TA的每日心情 | 奋斗 2016-1-29 12:24 |
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签到天数: 81 天 [LV.6]常住居民II
- 自我介绍
- 数学建模准备中...
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gancm 发表于 2014-7-19 12:30 ![]()
; G" g) ^1 K, o/ }6 u7 J# R1 y看了图我感觉是网络输出后面那几个值太大了,前面基本都是一条水平线了,具体哪里还看不出问题。你把修改的 ...
" [) D0 ?4 d) ~* X7 G+ a) m因为版本更新,Matlab中的Newff命令用法有所改变,原命令为:
8 e% U+ r, v, \4 \: f" Qnet=newff(dx,[3,7,2]{'tansig','tansig','purelin'},'traingdx');& T& S# d! I5 b& Z
我修改为:
& R* U y g4 v+ ^net=newff(p,t,[3,7,2],{'tansig','tansig','purelin'},'traingdx');
" {4 @. y- H6 R$ G然后有些命令被其他命令替代了,其中有premnmx,postmnmx,tramnmx命令好像被替换了,使用了一个强大的命令mapminmax。原命令为:
. O: T }' @/ L4 b& E7 ]# x[pn,minp,maxp,tn,mint,maxt]=premnmx(p,t);; w, F$ C$ T8 B6 g$ @
a=postmnmx(an,mint,maxt);/ V9 G" y$ H! p; `
pnewn=tramnmx(pnew,minp,maxp);& N9 H( n0 X2 Q' `, U
anew=postmnmx(anewn,mint,maxt)
: q$ v, T5 s. S. A" a我修改为:
( t! ^& H8 }* P0 p8 O[pn,ps1]=mapminmax(p);[tn,ps2]=mapminmax(t);
8 q. S$ D" V# k: U' s2 j# Qa=mapminmax('reverse',an,ps2);9 g2 A. e* m7 z4 x9 j9 U( Q
pnewn=mapminmax('apply',pnew,ps1);* I- k0 W; H% g, n6 P
anew=mapminmax('reverse',anewn,ps2)
/ ]# j+ A- T3 Z4 z0 @- P( g: {: a1 f+ ]: F1 A3 i
原程序为:
, k# S8 P. ]% o& z9 J4 `+ J1 W7 _$ s%原始数据输入 y, O+ V: ^# g( o. I+ @
clc
4 Q& w/ d/ I. V, U4 ?9 R3 S7 jsqrs=[20.55,22.44,25.73,27.13,29.45,30.1,30.96,34.06,36.42,38.09,39.13,39.99,...
0 _; k! @9 Y, I4 {2 {; h# O 41.93,44.59,47.30,52.89,55.73,56.76,59.17,60.63];$ t. l. C8 R# Z, d
sqjdcs=[0.6,0.75,0.85,0.90,1.05,1.35,1.45,1.60,1.70,1.85,2.15,2.20,2.25,2.35,...8 P2 |* c' h$ p; c% F1 h
2.5,2.6,2.7,2.85,2.95,3.10];$ @7 |+ v. M$ [% a( h/ A1 s& F
sqglmj=[0.09,0.11,0.11,0.14,0.20,0.23,0.23,0.32,0.32,0.34,0.36,0.36,0.38,0.49,..." l& A( b8 E; q" q7 I9 G0 U
0.56,0.59,0.59,0.67,0.69,0.79];' S/ Q* g) N* l9 h
glkyl=[5126,6217,7730,9145,10460,11387,12353,15750,18304,19836,21024,19490,20433,...
1 Y) ]& S8 y1 p! v) Z2 s- K 22598,25107,33442,36836,40548,42927,43462];7 v0 \6 y8 g& t1 T6 n
glhyl=[1237,1379,1385,1399,1663,1714,1834,4322,8132,8936,11099,11203,10524,11115,...
$ q0 i# W: g; @' X+ h4 N# X 13320,16762,18673,20724,20803,21804];
; c4 _/ m7 g3 \" jp=[sqrs;sqjdcs;sqglmj];4 Y4 [: \6 M- `
t=[glkyl;glhyl];
k/ @7 v2 H- p8 z* f: T$ ^
& J% F+ n3 a$ ]. V" {. a, |%数据归一化
$ d& u& h: }3 e& n* w[pn,minp,maxp,tn,mint,maxt]=premnmx(p,t);
' {* i" l. e2 Zdx=[-1,1;-1,1;-1,1];8 }: _4 ^' F# Z1 n" Y: h
( e i% G2 Q- F6 m; J
%BP网络训练
' q0 ?; Z. p: q5 ]: ~net=newff(dx,[3,7,2],{'tansig','tansig','purelin'},'traingdx');
1 i7 c2 k r. l+ f* _net.trainParam.show=1000;/ B9 V J4 ]; H! U1 f4 s+ F
net.trainParam.Lr=0.05;2 R, b4 g% I& s+ B+ O
net.trainParam.epochs=50000;6 u$ \- q. B# a0 |
net.trainParam.goal=0.65*10^(-3);
7 Z6 l' y+ |: w- [* P( v9 ]net=train(net,pn,tn);
( u; x- q- E% Q0 ?& k% Q7 B4 F7 `7 t( y9 k- T
%利用原数据对BP网络仿真
' Y6 y) |- Y0 ^$ c3 P4 man=sim(net,pn);2 W! l. v) a( H. r& V# ^& l
a=postmnmx(an,mint,maxt);( g+ J' A% d; t6 K6 K: @
( D) F# c9 U& y1 S( j6 B! Z# F
%仿真结果与原数据对比测试4 F# J6 T3 K9 ` t
x=1990:2009;* }1 {" l" Q. g2 @
newk=a(1, ;( ?8 C) F/ ?: Q$ L) P, Q0 M
newh=a(2, ;
; i1 ^" x/ `$ h. sfigure(2);
3 R/ Q5 n" R2 Z& o( dsubplot(2,1,1);plot(x,newk,'r-o',x,glkyl,'b--+');
! j0 D8 E, f" j7 k( t% alegend('网络输出客运量','实际客运量');
$ B2 z( T. v: t# wxlabel('年份');ylabel('货运量、万人');7 e, j. j; O6 R) y
title('运用工具箱客运量学习和测试对比图');/ v( G: X& o& c8 s4 }4 V
subplot(2,1,2);plot(x,newh,'r-o',x,glhyl,'b--+');
% }( J0 z1 l5 r8 _; e/ Ulegend('网络输出货运量','实际货运量');
% d- ^0 t3 i+ Z2 P( |xlabel('年份');ylabel('货运量、万吨');
; a- D/ J% q5 w# ^) Gtitle('运用工具箱货运量学习和测试对比图');
2 _" ]4 k0 w9 j# O" u
3 _8 @+ a0 B4 C2 E%新数据仿真2 x# w7 b8 v0 |! \+ c
pnew=[73.39,75.55
! B. w) \" K) ?8 Q 3.9635,4.0975. U7 L0 x9 {' M% D; W) C6 }
0.9880,1.0268];
6 F, @( b# t1 y1 N8 j. r0 ~pnewn=tramnmx(pnew,minp,maxp);
6 O+ k" A/ q, d4 f9 t! ^1 panewn=sim(net,pnewn);
3 p( @( [. I/ G1 L% n+ ]anew=postmnmx(anewn,mint,maxt)* ?8 i2 D: Y h( f# o
3 Y* `6 e, U+ ^, p修改后程序为:3 d6 U7 i% R% ?/ Y: o2 b9 @- {+ d
%原始数据输入! {0 n2 D" l# ^
clc
& W( ^" j% g7 z7 Qsqrs=[20.55,22.44,25.73,27.13,29.45,30.1,30.96,34.06,36.42,38.09,39.13,39.99,...
2 r9 o+ I b9 b 41.93,44.59,47.30,52.89,55.73,56.76,59.17,60.63];" \8 w6 v$ P4 H7 x% q6 t
sqjdcs=[0.6,0.75,0.85,0.90,1.05,1.35,1.45,1.60,1.70,1.85,2.15,2.20,2.25,2.35,...7 V. @2 h- w9 _
2.5,2.6,2.7,2.85,2.95,3.10];
5 E5 J: v* O7 | P% x2 f5 s/ Nsqglmj=[0.09,0.11,0.11,0.14,0.20,0.23,0.23,0.32,0.32,0.34,0.36,0.36,0.38,0.49,...
) e% {! a! O$ s9 s# w/ L 0.56,0.59,0.59,0.67,0.69,0.79];/ a. i/ i6 w4 s' _
glkyl=[5126,6217,7730,9145,10460,11387,12353,15750,18304,19836,21024,19490,20433,...
- g$ ~& g5 A$ N. {% q* e 22598,25107,33442,36836,40548,42927,43462];
) {0 @- a3 L+ {3 C# z3 [8 P" zglhyl=[1237,1379,1385,1399,1663,1714,1834,4322,8132,8936,11099,11203,10524,11115,...; M* Y5 A. q" e! N# a" g% f* A2 l
13320,16762,18673,20724,20803,21804];3 ?* {6 K6 h) m
p=[sqrs;sqjdcs;sqglmj];
/ H x0 Z7 y3 x5 p' l) at=[glkyl;glhyl];
`8 U5 ?8 E- o; M9 [) _& e; U0 q
: |/ ?' a) d/ j, `6 p; o* y%数据归一化
1 t% g1 b$ d: S# J2 U; X F+ S[pn,ps1]=mapminmax(p);( B8 s; S% u8 W7 ~# `
[tn,ps2]=mapminmax(t); ^" G! w, ~1 c! D0 B
% F" Z- l8 N( n8 G2 y%BP网络训练( l b/ _% M- J' c- l+ W; {6 i
net=newff(p,t,[3,7,2],{'tansig','tansig','purelin'},'traingdx');4 \7 s9 w, E) M1 k
net.trainParam.show=1000;
6 D9 L9 j; g9 u% U8 ]( X+ d* w0 hnet.trainParam.Lr=0.05;" h/ p, O- L/ D Y" R2 O
net.trainParam.epochs=50000;
7 i5 n! v x6 e7 Znet.trainParam.goal=0.65*10^(-3);
. e0 z" D" A$ Nnet=train(net,pn,tn);1 P1 H& |0 z0 C& Q' P
& ~8 H& o$ `3 B1 ~/ Q! B9 r5 B/ E
%利用原数据对BP网络仿真
- }$ f$ W$ b9 {( Y9 Z) B6 E: oan=sim(net,pn);2 ^1 T) }! |+ i, J& m" R- b4 v% U
a=mapminmax('reverse',an,ps2);% y* j/ H0 O0 ^+ Q
% w0 T/ N( R' ?* A ?* [- [%仿真结果与原数据对比测试! @ R7 ], t% e5 ?/ E. b
x=1990:2009;4 e. K+ W0 R" E8 L9 F2 O3 H
newk=a(1, ;
) a. V0 r, ?9 [; W: f6 Vnewh=a(2, ;
2 ~2 S- F! U# M7 ^/ C- S! J1 [! Rfigure(2);
% M; J' U* ]# h! z* bsubplot(2,1,1);plot(x,newk,'r-o',x,glkyl,'b--+');9 I0 ]% y! ?* ]. K: W) b8 _& ?/ V
legend('网络输出客运量','实际客运量');
/ {$ B# Z& M/ Z( }6 y# Jxlabel('年份');ylabel('货运量、万人');; i4 X: _- c- e+ }+ q- i
title('运用工具箱客运量学习和测试对比图');2 S k* a! ]) j5 O. F
subplot(2,1,2);plot(x,newh,'r-o',x,glhyl,'b--+');
" `7 ]5 U: o: P! z3 z- Nlegend('网络输出货运量','实际货运量');
" {: w7 ?% q5 M& Yxlabel('年份');ylabel('货运量、万吨');
0 \9 |" k A1 k, N: s9 ` |& etitle('运用工具箱货运量学习和测试对比图');
. h3 m& l4 S4 L! x( `
4 X3 B! b) v6 j% l* @( P# r%新数据仿真3 S2 C" W2 j' M1 o e- i6 z
pnew=[73.39,75.55: Q& h! {8 |& F8 h% l- W; h
3.9635,4.0975( K, y+ Z/ c+ |- P+ z$ H2 j
0.9880,1.0268];
# x# ~6 c$ v, H% u- Jpnewn=mapminmax('apply',pnew,ps1);9 S% d4 H9 B$ {0 E; v, V
anewn=sim(net,pnewn);
n; F6 a1 C: T2 H5 `6 B9 e$ _anew=mapminmax('reverse',anewn,ps2)- e; O& f5 |; b |9 e
(修改的地方用颜色标记了)' S; ?# l8 k1 }! Q/ Q6 l1 c b
麻烦您帮忙指出其中的问题,万分感谢! |
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