谁来帮忙看一下这个题错在哪里？

Winter_moon

Cryptoquote


Time Limit: 1000 ms Memory Limit: 65536 kB
Solved: 79 Tried: 281

Description
. H7 M2 w9 G9 _& G6 U* ~- VA cryptoquote is a ** encoded message where one letter is simply replaced by another throughout the message. For example:
" w  e+ d. c% H/ F
Encoded: HPC PJVYMIY
* c( ]2 D1 h( A2 l$ _6 ]4 f8 HDecoded: ACM CONTEST
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In the example above, H=A, P=C, C=M, J=O, V=N, Y=T, M=E and I=S. For this problem, you will decode messages.

# S  j+ H  _+ y5 S
+ C9 T6 \% Q) l# }1 h3 y: e; sInput
$ E! w# [+ r, C3 O7 n' ?The first line of input contains a single integer N,(1<=N<=1000) which is the number of data sets that follow. Each data set consists of two lines of input. The first line is the encoded message. The second line is a 26 character string of upper case letters giving the character mapping for each letter of the alphabet: the first character gives the mapping for A, the second for B and so on. Only upper case letters will be used. Spaces may appear in the encoded message, and should be preserved in the output string.

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2 T2 ]! \: m* h6 U, ~; l5 h7 b
Output
For each data set, you should generate one line of output with the following values: The data set number as a decimal integer (start counting at one), a space and the decoded message.

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9 I. G6 V" d/ v! f4 c, l, p2 ^" KSample Input
2
+ g' g7 u+ m5 ]+ R# {& w9 I: ^HPC PJVYMIY
" V2 z( S7 o8 }# j3 o& FBLMRGJIASOPZEFDCKWYHUNXQTV
FDY GAI BG UKMY
( H* `1 B7 E& s6 }! B; jKIMHOTSQYRLCUZPAGWJNBVDXEF

9 a0 ^# P& H, G* t; C) R) |8 v# V$ w
( N6 _) \8 Q1 s! w+ Y
Sample Output
. s& m) E4 o3 ?* i* r1 ACM CONTEST
" }& N5 g7 t  d3 ]( T0 }2 THE SKY IS BLUE



我的代码是：
, f. Y  Z  Q6 {, |  k#include<stdio.h>
# A8 C+ u4 J" F#include<string.h>
int main()
: @  K# S) t/ M, g1 T( H, ?{
( @4 A/ m! j' L5 j# e+ K; m; _     int N,i,j,k;
' Z& i2 o! \) `) P' D; b% L     char c;
     char code[1000];
     char map[27];
     char trans[1000];
     char wrong[3];
; W" [# r& _" [! g     scanf("%d",&N);
     gets(wrong);
     int h=1;
     while(N--)
     {
         gets(code);
         gets(map);
  l2 p8 M  z$ l8 w0 Q5 l         for(i=0;((c=code[i])!='\0');i++)
         {
             if(c==' ')trans[i]=' ';
             else {j=code[i]-'A';
             trans[i]=map[j];}       }
         printf("%d ",h);
         for(i=0;((k=trans[i]<=90)&&(k=trans[i]>=65)||(k=trans[i]==' '));i++)
         printf("%c",trans[i]);
         h++;
         printf("\n");
0 K% y3 i$ C* H  U( K( [: X     }
     return 0;
! B. C& U3 Q. h& v0 {$ _; R}


样例过了，但是提交答案的时候还是wrong answer。是哪里有陷阱？

zjqylcy

把答案也附上来吗。。。
! y6 U# Q/ x3 n% n" q3 T& H# z. h是不是k是int型？

葉_浅浅

.....................

linmatsas

C………………………………

_我还活着

没有看懂.....

huangliao6252

int h=1;这个定义应该在 scanf("%d",&N);前面。