Cryptoquote . f1 A A" I& @$ P9 Z! j
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1 e0 W& s$ o; a0 [+ x( A! ?Time Limit: 1000 ms Memory Limit: 65536 kB6 b j! L/ A7 i) _- _: D
Solved: 79 Tried: 281 ! r0 s9 K: `) C: \/ N
0 }( f8 B1 M! Q \+ B9 @Description 0 N; s: q0 q# \# q' s* ^ OA cryptoquote is a ** encoded message where one letter is simply replaced by another throughout the message. For example: 7 {+ s9 @; U' x% \- O+ d' w/ Z8 O* w( R; i( ^
Encoded: HPC PJVYMIY ( Y) f: i" h: U1 [, [9 l
Decoded: ACM CONTEST : B$ G6 \0 G3 ]2 @ / p$ X- Z" f: I8 ^In the example above, H=A, P=C, C=M, J=O, V=N, Y=T, M=E and I=S. For this problem, you will decode messages. " U5 i3 e6 m7 k; q& W 4 f7 \& D4 W, Z / t! i2 z$ }9 s) TInput ) {* H5 p* G2 v/ n% [1 c h% ^
The first line of input contains a single integer N,(1<=N<=1000) which is the number of data sets that follow. Each data set consists of two lines of input. The first line is the encoded message. The second line is a 26 character string of upper case letters giving the character mapping for each letter of the alphabet: the first character gives the mapping for A, the second for B and so on. Only upper case letters will be used. Spaces may appear in the encoded message, and should be preserved in the output string. 6 m' a0 T/ X$ [; S3 `7 z3 |6 F5 |; I3 }; k# G# B$ A2 z9 g/ v
8 Z7 J6 G7 F4 Z3 K0 F5 ^% o3 G$ b* P: ^
Output 3 H7 I# i0 F4 K' D
For each data set, you should generate one line of output with the following values: The data set number as a decimal integer (start counting at one), a space and the decoded message. , i3 _2 R% i5 u1 ?( t 1 D' @5 ]( ? {8 G0 y7 A n/ G8 a* ]6 ?" D2 x$ }1 P3 i: WSample Input : O; d8 o; P8 Q; A2 * ]- }. K. }3 V' p0 A* cHPC PJVYMIY ' _9 j3 \& A! |- @BLMRGJIASOPZEFDCKWYHUNXQTV 8 y# B% q* ]( P% ^) L
FDY GAI BG UKMY 7 o" z. u1 m9 p; S( d9 E
KIMHOTSQYRLCUZPAGWJNBVDXEF3 `' ?, @6 P6 L* B$ v. C
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( |2 W0 W) X- |* {$ }' M5 [7 r4 S3 s
Sample Output 1 X( t V: @9 ~: H1 ACM CONTEST ' \1 {4 }6 A/ Y
2 THE SKY IS BLUE E7 X' [ G* q3 }. l. |; e 7 P+ q3 R# n: G4 n$ q, ]* D- q# X) e3 l* x5 _0 k7 g6 a7 o
5 Q" ? o7 Q" R8 O7 w, H8 c
我的代码是: / s& t$ ]# [" c4 ?( z#include<stdio.h>7 z$ ?. u7 Y: k# k# B
#include<string.h> . S' P9 m$ ~- }+ ?. rint main() ! J% d9 C. O: V! L{6 r4 v. r6 q2 X5 y( F# G* }0 h
int N,i,j,k; ; j+ c$ b3 Q) z$ k" j2 U char c; 4 R, G4 Z, [( U/ W3 I+ p char code[1000]; ( _0 `1 y m0 H char map[27]; , M/ o: p0 s/ x1 |$ z- J) S- q char trans[1000];- H5 W; Q) U9 c" q+ M w9 H
char wrong[3];4 I, H$ d9 W: v% J/ c+ g
scanf("%d",&N); ' m0 G+ J& F1 e$ s+ f2 s gets(wrong);- C v' ?9 ?5 {3 V& y$ i U. D
int h=1;1 R" T3 g* _. `# F8 `- U% o4 G
while(N--) H6 ^& l" U# k2 k* R( d
{ ; V1 I# a6 t6 ] gets(code);/ H2 v* L0 d+ u; B ?% o0 W9 Q
gets(map);' ` b Q: Q" S/ ~3 k, o4 b0 I
for(i=0;((c=code[i])!='\0');i++); G8 s; x8 L( r
{ & O: F6 o8 x5 v! e e* n1 b( n if(c==' ')trans[i]=' ';4 u2 X; V! k; Z4 f2 c
else {j=code[i]-'A'; ! _# M& N8 }! a! ? trans[i]=map[j];} } 2 T6 b/ W& L) w printf("%d ",h); / d/ K* b8 T4 I! c for(i=0;((k=trans[i]<=90)&&(k=trans[i]>=65)||(k=trans[i]==' '));i++) $ m% B0 w$ X- k: E printf("%c",trans[i]);) L" k0 @" f( d+ n$ T
h++;& p5 a w1 l* v4 Y
printf("\n");7 p. H* g2 r7 k& [
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return 0; / Y# I6 P2 Q/ r3 H1 s} * L+ l) d3 q; k& J9 [ m 7 z0 |6 X A: D : B* i+ g% ]* \) o+ m' f样例过了,但是提交答案的时候还是wrong answer。是哪里有陷阱?! z- |/ l o0 L+ ]8 z