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升级   79.5% TA的每日心情 | 奋斗 2016-1-29 12:24 |
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签到天数: 81 天 [LV.6]常住居民II
- 自我介绍
- 数学建模准备中...
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gancm 发表于 2014-7-19 12:30 3 ~8 _; g* \2 x# g- O: o
看了图我感觉是网络输出后面那几个值太大了,前面基本都是一条水平线了,具体哪里还看不出问题。你把修改的 ... % f) d% t5 C: _/ |% W: e% v( v& @
因为版本更新,Matlab中的Newff命令用法有所改变,原命令为:9 x. G9 @) C$ B$ q4 Q% ?
net=newff(dx,[3,7,2]{'tansig','tansig','purelin'},'traingdx');
. _' c1 B# S, a; x+ X我修改为:
3 _- c; o6 x+ q7 V4 Snet=newff(p,t,[3,7,2],{'tansig','tansig','purelin'},'traingdx');
8 e0 g; d7 J* H8 S然后有些命令被其他命令替代了,其中有premnmx,postmnmx,tramnmx命令好像被替换了,使用了一个强大的命令mapminmax。原命令为:- G; n5 _. ^- b- c4 O
[pn,minp,maxp,tn,mint,maxt]=premnmx(p,t);
% m4 L3 N+ [6 J; H1 @8 Za=postmnmx(an,mint,maxt);1 o) o; X* J4 ?( R& Y
pnewn=tramnmx(pnew,minp,maxp);9 m2 a! ?2 j4 o9 u6 p
anew=postmnmx(anewn,mint,maxt)( R- V6 i# v- Q" q8 D' c5 u! b
我修改为:) L5 t1 W3 P; b: V
[pn,ps1]=mapminmax(p);[tn,ps2]=mapminmax(t);1 Y% K7 \9 `+ r! ?1 `7 V( d9 x+ F
a=mapminmax('reverse',an,ps2);0 y& @8 X% B; Z2 c3 j$ K
pnewn=mapminmax('apply',pnew,ps1);# Y3 i5 @& a. ?* L/ p
anew=mapminmax('reverse',anewn,ps2)% ~9 W( o! V" c4 K; ~1 s* ^ i% [
/ K1 f r- h6 C6 ~! C9 C" E$ T
原程序为:' t" w4 ]$ W) f+ k6 L$ A$ d# V
%原始数据输入
, m- [+ @ w# t* }1 bclc
9 s/ k* j3 b9 {/ x& C+ @sqrs=[20.55,22.44,25.73,27.13,29.45,30.1,30.96,34.06,36.42,38.09,39.13,39.99,...3 Z1 n S) W) t
41.93,44.59,47.30,52.89,55.73,56.76,59.17,60.63];; {) K; @/ h+ N7 u9 w/ d1 Z e
sqjdcs=[0.6,0.75,0.85,0.90,1.05,1.35,1.45,1.60,1.70,1.85,2.15,2.20,2.25,2.35,...
* l' k: S7 H; d- v, Y2 l4 w/ u 2.5,2.6,2.7,2.85,2.95,3.10];
' c# w) q% C& h' g# T+ M" jsqglmj=[0.09,0.11,0.11,0.14,0.20,0.23,0.23,0.32,0.32,0.34,0.36,0.36,0.38,0.49,...* y9 j7 g; g5 p; H% S
0.56,0.59,0.59,0.67,0.69,0.79];
8 y c9 }+ G# c3 R! ^3 ^glkyl=[5126,6217,7730,9145,10460,11387,12353,15750,18304,19836,21024,19490,20433,...0 i: F; [ {$ q% f" t
22598,25107,33442,36836,40548,42927,43462];
) J. R# A3 L, x( Cglhyl=[1237,1379,1385,1399,1663,1714,1834,4322,8132,8936,11099,11203,10524,11115,...1 m3 A* ~' R6 [6 L9 n' r
13320,16762,18673,20724,20803,21804];! O+ i" Z. l3 t& g
p=[sqrs;sqjdcs;sqglmj];2 p: N+ u" v$ A+ g( \: d8 z
t=[glkyl;glhyl];4 A9 P. G, U$ L6 o w+ S7 i
" _, R' E& @6 d) x9 \! ]! g# L
%数据归一化+ T+ [7 A/ y, P9 D
[pn,minp,maxp,tn,mint,maxt]=premnmx(p,t);( @8 }# Z% S% G1 w v; c
dx=[-1,1;-1,1;-1,1];
/ d% o9 Q/ h6 w3 Y( D# S- r. Q3 y2 o* O+ V z$ l; C, _
%BP网络训练
; ?. y; Z5 F. ^) R' w8 \6 Q5 O' Snet=newff(dx,[3,7,2],{'tansig','tansig','purelin'},'traingdx');# k6 f! l- ~9 G3 N) v
net.trainParam.show=1000;
, d# C6 ~1 V$ F- Dnet.trainParam.Lr=0.05;0 y( ~" a4 T5 S, h
net.trainParam.epochs=50000;" o1 B) c' E1 K h: T! Y/ K
net.trainParam.goal=0.65*10^(-3);
3 C7 ~8 I$ c. qnet=train(net,pn,tn);; [3 d& B7 p' |4 `. j' k. D0 D* }
+ v! M2 I* \" Y4 `! T0 g, j" D
%利用原数据对BP网络仿真
( f0 Z2 U- l( e# R& p1 Wan=sim(net,pn);: \9 F4 z) I2 W* s
a=postmnmx(an,mint,maxt);2 d' q) G0 t- ]( G" E3 g) v
3 I6 q5 E B) e |& k$ `+ z%仿真结果与原数据对比测试
, x* y5 Z+ P+ H. L5 Q, Xx=1990:2009;9 W2 e( a8 ?0 U$ z
newk=a(1, ;
: b9 s" }! P: L4 Rnewh=a(2, ;
4 X- O$ K# u/ Z5 afigure(2);
$ ]& |+ B0 D8 ~, r: H9 jsubplot(2,1,1);plot(x,newk,'r-o',x,glkyl,'b--+');" i0 \8 J9 D+ ^0 G1 k) A Y; t
legend('网络输出客运量','实际客运量');# Z1 o& ~+ f! Y- o
xlabel('年份');ylabel('货运量、万人');
! h0 ~5 r' R" M" z+ Etitle('运用工具箱客运量学习和测试对比图');
! W9 W& Y7 l. F( q2 zsubplot(2,1,2);plot(x,newh,'r-o',x,glhyl,'b--+');9 T4 k- a7 j6 S( Y4 ~' a
legend('网络输出货运量','实际货运量');
1 W4 t# i" Q ?6 e1 S, i2 jxlabel('年份');ylabel('货运量、万吨');4 I$ A, o0 P. w3 A& _+ y
title('运用工具箱货运量学习和测试对比图');
4 h/ P* b$ l# s0 j* ?+ d7 a9 @$ q- a& f- k- c
%新数据仿真
- `9 k2 P1 A+ I+ F4 r+ rpnew=[73.39,75.55) o0 {8 [0 ]! N! M
3.9635,4.0975, _% Q7 m* g0 {* ^- i
0.9880,1.0268];; Q1 b$ c0 ]! V9 U
pnewn=tramnmx(pnew,minp,maxp);
/ x, A3 c2 f# b- }9 P$ Manewn=sim(net,pnewn);& q c8 n! G% O/ R) T
anew=postmnmx(anewn,mint,maxt)
( G( h" J1 N1 a6 U9 H% \0 J% V1 x4 L. F2 L* H$ G
修改后程序为:
: d K5 X1 X4 [9 S0 l%原始数据输入
4 B3 ~0 u! k# I2 _% \* S" P6 a- v' Qclc
& I" r' |/ a; m# g( ^5 C( [+ ]( Tsqrs=[20.55,22.44,25.73,27.13,29.45,30.1,30.96,34.06,36.42,38.09,39.13,39.99,...
2 i% u+ |1 }. g! a 41.93,44.59,47.30,52.89,55.73,56.76,59.17,60.63];
- s, |% O! _' |0 asqjdcs=[0.6,0.75,0.85,0.90,1.05,1.35,1.45,1.60,1.70,1.85,2.15,2.20,2.25,2.35,...
, `* }2 I) p0 q 2.5,2.6,2.7,2.85,2.95,3.10];% W& j5 N$ g+ }/ l i0 C6 Z9 A) q9 J7 g4 f
sqglmj=[0.09,0.11,0.11,0.14,0.20,0.23,0.23,0.32,0.32,0.34,0.36,0.36,0.38,0.49,..., v" W% q( I# V1 F# R
0.56,0.59,0.59,0.67,0.69,0.79];
; Q0 J* S: V7 Q$ t+ N1 jglkyl=[5126,6217,7730,9145,10460,11387,12353,15750,18304,19836,21024,19490,20433,...8 q- c: F8 r: c a/ ^$ e
22598,25107,33442,36836,40548,42927,43462];) h9 {1 L# f& f" O) n3 o
glhyl=[1237,1379,1385,1399,1663,1714,1834,4322,8132,8936,11099,11203,10524,11115,...
$ e/ D, D( j3 H9 Z* s- Z 13320,16762,18673,20724,20803,21804];" f. L* v1 D) ]! C$ P1 B
p=[sqrs;sqjdcs;sqglmj];0 n' |: U+ J; L5 E" ]; a
t=[glkyl;glhyl];. s- J# H$ ~' N) N6 t3 u) d; w
( h% `0 T5 k6 R%数据归一化
5 p6 I) E; D# _) |- _ i0 ?[pn,ps1]=mapminmax(p);% x d/ N% L) \, l1 p
[tn,ps2]=mapminmax(t);
1 J# `( ^! b# U ]" U% B. e, y+ P% K' r* g4 ~
%BP网络训练
# N' E& g& K0 z# `& k+ Tnet=newff(p,t,[3,7,2],{'tansig','tansig','purelin'},'traingdx');4 }0 m, F% L3 V* ~) c
net.trainParam.show=1000;
) O, u1 H: p) e) d5 b$ D; cnet.trainParam.Lr=0.05;
8 {, ^; C. W) G3 h0 W6 Vnet.trainParam.epochs=50000;
3 U! s' Y! C7 |* _) g6 t. R6 Cnet.trainParam.goal=0.65*10^(-3);- r" k9 O2 Y9 v+ _, N) ^" r
net=train(net,pn,tn);& P% t5 K& a, _6 ~' E) F
4 N% U; J) D7 L$ F
%利用原数据对BP网络仿真 V6 ^7 X7 A1 f* m/ V8 }0 J
an=sim(net,pn);- y7 @! `+ [5 \
a=mapminmax('reverse',an,ps2);9 a# T& Q. N2 Z" {, i. D( ?. ]# \
* e/ L! A" w* T! h$ P" b+ Q* A
%仿真结果与原数据对比测试2 c2 [$ A* g% w, _- E
x=1990:2009;
4 c. R, x: w8 Znewk=a(1, ;$ _- J0 ]" ~& ^& W1 N h7 M
newh=a(2, ;
. d6 D, z- I: ^$ m- e7 vfigure(2);0 t8 [/ g) V$ O' M/ M0 c
subplot(2,1,1);plot(x,newk,'r-o',x,glkyl,'b--+');7 J$ E5 Q; X5 [' |
legend('网络输出客运量','实际客运量');
& z' a+ g" ^9 x! Oxlabel('年份');ylabel('货运量、万人');
% ]0 g" Q/ H8 |title('运用工具箱客运量学习和测试对比图');
1 B X; o) G" R0 B3 Fsubplot(2,1,2);plot(x,newh,'r-o',x,glhyl,'b--+');
; w. g' C) U9 `- `+ l! H# ?legend('网络输出货运量','实际货运量');
9 S3 J/ z( U( V! C& i2 s) P& Bxlabel('年份');ylabel('货运量、万吨');' a- \0 |& B" G) U7 I
title('运用工具箱货运量学习和测试对比图');* t. Y0 ?) V9 C- H# A. |" P
$ P5 E7 {# ~% a6 A3 I2 o6 o2 }. I%新数据仿真, ^+ O! f7 v2 L! m$ [# R1 W( r' X
pnew=[73.39,75.55" h/ J/ s5 _! _1 U ]1 i9 ]
3.9635,4.0975
! G9 q% t( K/ Y# { 0.9880,1.0268];. `% u) s. \/ h- V# |' N
pnewn=mapminmax('apply',pnew,ps1);; d- Q6 b" T! p; g B$ J( q9 K* [
anewn=sim(net,pnewn);2 q! f7 d6 \6 f" @! G* |
anew=mapminmax('reverse',anewn,ps2)
! x" v( y/ D5 Y% c1 [ s5 Z0 O# n9 S(修改的地方用颜色标记了)8 V; ^% J$ T: s+ @
麻烦您帮忙指出其中的问题,万分感谢! |
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